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Zepler [3.9K]
3 years ago
7

How can density be used to determine the identity of a pure substance?

Chemistry
1 answer:
OLEGan [10]3 years ago
5 0

Answer:

Explanation:

You can identify an unknown substance by measuring its density and comparing your result to a list of known densities. Density = mass/volume. Assume that you have to identify an unknown metal.

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In boyle's law, the initial volume of a gas is 120 ml at 256 kpa. what will be the volume if the pressure increases to 385 kpa?
Vinil7 [7]
<h3>Answer:</h3>

79.8 ml

<h3>Explanation:</h3>

Boyle's law describes the relationship between pressure and volume when the temperature is constant. For this question, I will be rounding to significant figures.

Boyle's Formula

When describing the relationship between pressure and volume, the formula \displaystyle P_{1} V_{1}= P_{2} V_{2}. In this formula, P_{1}V_{1} is the initial pressure and volume. On the other side, P_{2} V_{2} is final pressure and volume. So, to find a missing variable you must plug in the values you are given.

Final Volume

Remember when solving this question to remain constant in your units. When we plug in the values we know we are given:

  • 256kPa*120mL=385kPa*V_{2} mL

Now, we can multiply the left side

  • 30720kPa*mL=385kPa*V_{2} mL

Finally, we can divide by 385 to isolate the final volume

  • 79.8mL=V_{2}

This gives the final volume of 79.8mL.

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2 years ago
How many molecules of oxygen gas (O2) are in 8 grams of oxygen
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Answer:Hence, in 8g of Oxygen molecules, there are 3. 011 x 10²³ Oxygen atoms. In this way, how many moles are in 16 grams of oxygen? In other words, 1 mole of oxygen would contain molecules

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Please help me with this question
Leviafan [203]

1. The resulting concentration will be 0.00044 mol/L

2. The minimum mass of sodium sulfite to add will be 0.4032 grams.

<h3>Stoichiometric problems</h3>

1. Using m1v1=m2v2

  m1 = 0.01 mol/L, v1 = 20 mL, v2 = 450 mL

 

       m2 = m1v1/v2 = 0.01 x 20/450 = 0.00044 mol/L

2. Na_2SO_3 + Ca(NO_3)_2 --- > 2NaNO_3 + CaSO_3

Mole ratio of the reactants = 1:1

Mole of 80 mL, 0.0400 mol/L Ca(NO3)2 = 80/1000 x 0.0400 = 0.0032 mol

Equivalent mole of Na2SO3 = 0.0032 moles

Mass of 0.0032 moles Na2SO3 = 0.0032 x 126 = 0.4032 grams

Thus, the minimum mass of sodium sulfite to be added must be 0.4032 grams.

More on stoichiometric calculations can be found here: brainly.com/question/27287858

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