Answer: 365 K
Explanation:
According to the Arrhenius equation,

or,
![\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7BK_2%7D%7BK_1%7D%29%3D%5Cfrac%7BEa%7D%7B2.303%5Ctimes%20R%7D%5B%5Cfrac%7B1%7D%7BT_1%7D-%5Cfrac%7B1%7D%7BT_2%7D%5D)
where,
= rate constant at
= 1.00
= rate constant at
= 5.00
= activation energy for the reaction = 28.90 kJ/mol= 28900 j/mol
R = gas constant = 8.314 J/mole.K
= initial temperature = 313 K
= final temperature = ?
Now put all the given values in this formula, we get
![\log (\frac{5.00}{1.00})=\frac{28900}{2.303\times 8.314J/mole.K}[\frac{1}{313K}-\frac{1}{T_2K}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7B5.00%7D%7B1.00%7D%29%3D%5Cfrac%7B28900%7D%7B2.303%5Ctimes%208.314J%2Fmole.K%7D%5B%5Cfrac%7B1%7D%7B313K%7D-%5Cfrac%7B1%7D%7BT_2K%7D%5D)
![0.69=\frac{28900}{2.303\times 8.314J/mole.K}[\frac{1}{313K}-\frac{1}{T_2K}]](https://tex.z-dn.net/?f=0.69%3D%5Cfrac%7B28900%7D%7B2.303%5Ctimes%208.314J%2Fmole.K%7D%5B%5Cfrac%7B1%7D%7B313K%7D-%5Cfrac%7B1%7D%7BT_2K%7D%5D)

Therefore, 365 K is required to increase the reaction rate by 5.00 times.
Answer:
It is a solution
Explanation:
I know that because a solution is something you mix and you have to use a microscope if you really wanna see what's in there
Answer : The final pressure of the basketball is, 0.990 atm
Explanation :
Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

or,

where,
= initial pressure = 1.10 atm
= final pressure = ?
= initial temperature = 
= initial temperature = 
Now put all the given values in the above equation, we get:


Thus, the final pressure of the basketball is, 0.990 atm
<span>a.655 k not 100 percent on this but try it. You will use 273.15 and add your Celcius temp to get it in Kelvin
</span>
The balanced equation for
Ca(OH)2 + H3PO4→ Ca3(PO4)2 + H2O is
3 Ca(OH)2 +2 H3PO4→ Ca3(Po4)2 + 6 H2O
3 moles of Ca(OH)2 reacted with 2 moles of H3PO4 to form 1 mole of Ca3(PO4)2 and 6 moles of H2O