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navik [9.2K]
3 years ago
6

PLEASE HELP!!!

Chemistry
1 answer:
ladessa [460]3 years ago
7 0

Answer:

the answer is c. [.4r]3d104324p

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What is the total number of oxygen atoms represented in the formula na2c03.10h2o?
Wewaii [24]

As per the given chemical formula- Na2CO3.10H2O, one mole of the chemical compound contains 13 moles of oxygen atoms. Hence

Number of moles of oxygen atoms in one mole of Na2CO3.10H2O = 13

number of moles of oxygen atoms in 0.2 moles of Na2CO3.10H2O = 13 X 0.2 = 2.6

Now, one mole of a substance contains 6.022 X 10^23 particles of the substance. Thus

number of atoms of oxygen in one mole of oxygen atom = 6.022 X 10^23

number of moles of oxygen atoms in 2.6 moles of oxygen atoms = 2.6 X 6.022 X 10^23 = 15.657 X 10^23

= 1.566 X 10^24

Thus, there are 1.566 X 10^24 atoms of oxygen in 0.2 moles of Na2CO3.10H2O.
4.7
7 0
3 years ago
The movement of one or more from one reactant to another is called
mrs_skeptik [129]

Answer: Redox Reaction

Explanation:

Redox reaction is the key chemical events in an oxidation-reduction also called Redox. It is the net movement of electrons from one reactants to another

7 0
3 years ago
Common additives to drinking water include elemental chlorine, chloride ions, and phosphate ions. Recently, reports of elevated
NeX [460]

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

8 0
3 years ago
Find the mass of 4.5 moles of H3PO4
Contact [7]

Hey there!

H₃PO₄

Find molar mass.

H: 3 x 1.008 = 3.024

P: 1 x 30.97 = 30.97

O: 4 x 16 = 64

---------------------------------

                  97.994 grams

The mass of 1 mole of H₃PO₄ is 97.994 grams.

We have 4.5 moles.

97.994 x 4.5 = 440

The mass of 4.5 moles of H₃PO₄ is 440 grams.

Hope this helps!

6 0
2 years ago
Under standard-state conditions, which of the following half-reactions occurs at the cathode during the electrolysis of aqueous
Slav-nsk [51]

Answer:

The following reaction will occur at cathode:

Ni^{+2}(aq)+2e--->Ni(s)

Explanation:

The two half reaction during electrolysis of aqueous nickel sulfate will be

a) anode reaction :

Water will undergo oxidation and will evolve oxygen gas at anode as shown in the given reaction:

2H_{2}O(l) ----> O_{2}(g) + 4H^{+}(aq) + 4e

b) Cathode reaction: The reduction of Nickel ion will occur by gain of two electrons as shown in the given equation:

Ni^{+2}(aq)+2e--->Ni(s)

Thus the overall reaction will be:

2H_{2}O(l) + 2Ni^{+2}----> O_{2}(g) + 4H^{+}(aq) + 2Ni(s)

6 0
2 years ago
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