Question

In boyle's law, the initial volume of a gas is 120 ml at 256 kpa. what will be the volume if the pressure increases to 385 kpa?

Answer 1

Answer:

79.8 ml

Explanation:

Boyle's law describes the relationship between pressure and volume when the temperature is constant. For this question, I will be rounding to significant figures.

Boyle's Formula

When describing the relationship between pressure and volume, the formula $\displaystyle P_{1} V_{1}= P_{2} V_{2}$. In this formula, $P_{1}V_{1}$ is the initial pressure and volume. On the other side, $P_{2} V_{2}$ is final pressure and volume. So, to find a missing variable you must plug in the values you are given.

Final Volume

Remember when solving this question to remain constant in your units. When we plug in the values we know we are given:

• $256kPa*120mL=385kPa*V_{2} mL$

Now, we can multiply the left side

• $30720kPa*mL=385kPa*V_{2} mL$

Finally, we can divide by 385 to isolate the final volume

• $79.8mL=V_{2}$

This gives the final volume of 79.8mL.