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3 years ago

Write an equation that involves

Mathematics

2 answers:

Romashka [77]3 years ago

7 0

so the solution is 5 we'll start with that

x=5

to do reverse multiplcation, you must divide so

x=5

x/10=5/10

x/10=1/2

then the other problem

x=5

5x=25

to solvve

x/10=1/2

multiply by 10

x=5

then

5x=25

divide both sides by 5

x=5

Lilit [14]3 years ago

6 0

We can use any equation, as long as it’s solution is 5.

So, 4x(5+x)-2(5x+2x^2)=50

10x=50

x=5

Now, to use division:

20x/10+ 4x^2/4x^2=11

Simplifying we get:

2x+1=11

2x=10
x=5.

This is a little complicated, but I hope this helps!

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Can you show the steps thanks .........

Andrews [41]

Answer:

40 black bears

Step-by-step explanation:

Hope it helps.

5 per sample

8 samples

5 x 8 = 40 black bears

4 0

2 years ago

What type of model best fits the height of a tree increases by 2.5 feet each growing season

Thepotemich [5.8K]

Answer:

Step-by-step explanation:

A linear graph with y values (height of tree) going up 2.5 with each increase of x (growing season)

This is the model that best fits the graph describing a growth of a plant

3 0

3 years ago

In a recent survey 55% of pet owners have more than one pet if there was 620 pet owners survey which proportion could be used to

Alika [10]

Answer:

341..

Step-by-step explanation:

i would personally say 341 because 620 multiplied by 55% or .55, as written on a calculator, would be 341.

5 0

3 years ago

2 (h-8)-h = h-16 what is the solution

Svetach [21]

Let's solve your equation step-by-step.2(h−8)−h=h−16Step 1: Simplify both sides of the equation.2(h−8)−h=h−16Simplify: (Show steps)h−16=h−16Step 2: Subtract h from both sides.h−16−h=h−16−h−16=−16
Step 3: Add 16 to both sides.−16+16=−16+160=0Answer:All real numbers are solutions.

6 0

3 years ago

How do you find the equation of a triangles altitude using point slope formula?

forsale [732]

1. An altitude of a triangle is a line segment from a vertex perpendicular to the opposite side. Find the equations of the altitudes of the triangle with vertices (4, 5),(-4, 1) and (2, -5). Do this by solving a system of two of two of the altitude equations and showing that the intersection point also belongs to the third line. 
(Scroll Down for Answer!)Answer by jim_thompson5910(34047) (Show Source):You can put this solution on YOUR website!
If we plot the points and connect them, we get this triangle:

Let point
A=(xA,yA)
B=(xB,yB)
C=(xC,yC)

-------------------------------
Let's find the equation of the segment AB

Start with the general formula

Plug in the given points

Simplify and combine like terms

So the equation of the line through AB is

-------------------------------
Let's find the equation of the segment BC

Start with the general formula

Plug in the given points

Simplify and combine like terms

So the equation of the line through BC is

-------------------------------
Let's find the equation of the segment CA

Start with the general formula

Plug in the given points

Simplify and combine like terms

So the equation of the line through CA is

So we have these equations of the lines that make up the triangle

So to find the equation of the line that is perpendicular to that goes through the point C(2,-5), simply negate and invert the slope to get

Now plug the slope and the point (2,-5) into

Solve for y and simplify

So the altitude for vertex C is

Now to find the equation of the line that is perpendicular to that goes through the point A(4,5), simply negate and invert the slope to get

Now plug the slope and the point (2,-5) into

Solve for y and simplify

So the altitude for vertex A is

Now to find the equation of the line that is perpendicular to that goes through the point B(-4,1), simply negate and invert the slope to get

Now plug the slope and the point (-4,1) into

Solve for y and simplify

So the altitude for vertex B is

------------------------------------------------------------
Now let's solve the system

Plug in into the first equation

Add 2x to both sides and subtract 2 from both sides

Divide both sides by 3 to isolate x

Now plug this into

So the orthocenter is (-2/3,1/3)

So if we plug in into the third equation , we get

So the orthocenter lies on the third altitude

3 0

3 years ago