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3 years ago

Write an equation that involves

Mathematics

2 answers:

Romashka [77]3 years ago

7 0

so the solution is 5 we'll start with that

x=5

to do reverse multiplcation, you must divide so

x=5

x/10=5/10

x/10=1/2

then the other problem

x=5

5x=25

to solvve

x/10=1/2

multiply by 10

x=5

then

5x=25

divide both sides by 5

x=5

Lilit [14]3 years ago

6 0

We can use any equation, as long as it’s solution is 5.

So, 4x(5+x)-2(5x+2x^2)=50

10x=50

x=5

Now, to use division:

20x/10+ 4x^2/4x^2=11

Simplifying we get:

2x+1=11

2x=10
x=5.

This is a little complicated, but I hope this helps!

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Evaluate 15/5 + 40 . 7 - 3 to the power of 4.

Lina20 [59]

15/5 + 40.7 -3^4
= 3 + 40.7 - 81
= -37.3

hope this helps! :)))

4 0

3 years ago

The fictional rocket ship Adventure is measured to be 65 m long by the ship's captain inside the rocket.When the rocket moves pa

Gwar [14]

Answer:

a) t₀ = 1.73205 s

b) 1.0 C

Step-by-step explanation:

(A)

The time dilation (t) observed by an observer at rest relative to the time (t₀) measured by observer in motion is;

$t = \frac{t_0}{\sqrt{1 - \frac{V^2}{C^2}}}$

$t_0 = t \sqrt{1 - \frac{V^2}{C^2}}$ time measured by captain

⇒ $t_0 = 2.0 \sqrt{1 - \frac{0.5^2C^2}{C^2}}$ V = 0.5 c

⇒ t₀ = 1.73205 s

(B)

Speed of the light never exceeds by its real value. The speed of the light in any frame of reference is constant.

∵ It will be "1.0C" or just "C"

7 0

3 years ago

Parallel lines in space are coplanar.

kakasveta [241]

Coplanar lines are line witch lie on the same lie on the same plane. two parallel lines or two intersecting lines always lie in a plane. Thus, two line are coplanar, if and only if they are either parallel or intersecting. lines in three dimensional space are coplanar, only if they are not skewed lines.

3 0

3 years ago

Mr.Ward runs a lot. He ran 45 minutes each day, 5 days each week , for 16 weeks . In that time, he ran 450 miles. What was his a

Savatey [412]

Answer:

7.5 miles per hour.

Step-by-step explanation:

We have been given that Mr. Ward runs a lot. He ran 45 minutes each day, 5 days each week, for 16 weeks.

First of all, we will find time for that Mr. Ward ran in 16 weeks.

We will multiply 5 by 16 to find number of days for that Mr. Ward ran and then we will multiply the result by 45 minutes to find the time.

$\text{Time for that Mr. Ward ran in 16 weeks}=16\times 5\times 45\text{ minutes}$