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3 years ago

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Which of these number words represents the numeral 4,056? four thousand, five hundred six four thousand, five hundred fifty-six

four thousand, fifty-six four thousand, sixty-five

2 answers:

dimaraw [331]3 years ago

7 0

Four thousand, fifty-six

hjlf3 years ago

4 0

Solution:

we have been asked to find

Which of the given number words represents the numeral 4,056?

Its about the counting.

On unit place we have 6.

on Tenth place we have 5.

on hundredth place we have 0.

On Thousand place we have 4.

so in our number word representation there will be no "Hundreds".

So it will make

Hence the given number words representing the numeral 4,056 is Four thousands and fifty six

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If I put a different sticker on the 30th, 50th, and 60th pages will any of the first 600 pages have all 3 stickers?

icang [17]

Answer:

so the which page that will have the 3 sticker, we must solve the least common multiple of 30, 50, 60. A common multiple is a number that is a multiple of two or more numbers. The common multiples of 3 and 4 are 0, 12, 24, ....

The least common multiple (LCM) of two numbers is the smallest number (not zero) that is a multiple of both.

so the least common multiple of 30, 50 and 60 is 300. so the page that will have 3 stickers is 300th page

Step-by-step explanation:

8 0

3 years ago

Kareem wrote the values shown below.

grandymaker [24]

Answer:

Option D is correct.

$\lfloor 4.8 \rfloor$ and $\lceil 3.2 \rceil$

Step-by-step explanation:

Floor function states that the greatest integer that is less than or equal to x.

It is represented by: $\lfloor x \rfloor$

Ceiling function states that the least integer that is greater than or equal to x.

It is represented by: $\lceil x \rceil$

As per the statement:-

Kareem wrote the values show below:

$\lceil 3.2 \rceil$ , $\lfloor 2.7 \rfloor$ , $\lceil 2.9 \rceil$ and $\lfloor 4.8 \rfloor$ .

by definition:

$\lceil 3.2 \rceil$ = 4

$\lfloor 2.7 \rfloor$ = 2

$\lceil 2.9 \rceil$ =3

$\lfloor 4.8 \rfloor$ = 4

From the given options only pair which is equivalent is:

$\lfloor 4.8 \rfloor$ and $\lceil 3.2 \rceil$

7 0

3 years ago

Karen measures the width of a garden plot and records that it is 44.25 meters. Its actual width is 45.5 meters.

vazorg [7]

Answer

Find out the what is the percent error in the measurement, to the nearest tenth of a percent .

To prove

Formula

$Percentage\ error = \frac{error\times 100}{exact}$

Where error = | Approx - Exact |

As given

Karen measures the width of a garden plot and records that it is 44.25 meters. Its actual width is 45.5 meters.

Approx value = 44.25 meters

Actual value = 45.5 meters

error = | 44.25 - 45.5 |

= |-1.25|

= 1.25

Put in the formula

$Percentage\ error = \frac{1.25\times 100}{45.5}$

$Percentage\ error = \frac{125}{45.5}$

Percentage error = 2.7%

Therefore the percentage error is 2.7% .

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3 years ago

The booster club needs to raise at least $6,000 for new football uniforms. So far, they have raised $1,200.

lana66690 [7]

Answer:

• Let x be the number of members

• In inequalities, at least means greater or equal ( ≥ )

${ \underline{ \mathfrak{ \: answer : }}}$

${ \boxed{ \boxed{ \rm{x + 1200 \geqslant 6000}}}}$

• To get the average, substitute for x as 99 and amount collected by each member

3 0

3 years ago

1. Write the form of the partial fraction decomposition of the rational expression. Do not solve for the constants.

german

Answer:

Step-by-step explanation:

1.

To write the form of the partial fraction decomposition of the rational expression:

We have:

$\mathbf{\dfrac{8x-4}{x(x^2+1)^2}= \dfrac{A}{x}+\dfrac{Bx+C}{x^2+1}+\dfrac{Dx+E}{(x^2+1)^2}}$

2.

Using partial fraction decomposition to find the definite integral of:

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}dx$

By using the long division method; we have:

$x^2-8x-20 | \dfrac{2x}{2x^3-16x^2-39x+20 }$

$- 2x^3 -16x^2-40x$

<u> </u>

$x+ 20$

So;

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x+\dfrac{x+20}{x^2-8x-20}$

By using partial fraction decomposition:

$\dfrac{x+20}{(x-10)(x+2)}= \dfrac{A}{x-10}+\dfrac{B}{x+2}$

$= \dfrac{A(x+2)+B(x-10)}{(x-10)(x+2)}$

x + 20 = A(x + 2) + B(x - 10)

x + 20 = (A + B)x + (2A - 10B)

Now; we have to relate like terms on both sides; we have:

A + B = 1 ; 2A - 10 B = 20

By solvong the expressions above; we have:

$A = \dfrac{5}{2}$ $B = \dfrac{3}{2}$

Now;

$\dfrac{x+20}{(x-10)(x+2)} = \dfrac{5}{2(x-10)} + \dfrac{3}{2(x+2)}$

Thus;

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)}$

Now; the integral is:

$\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = \int \begin {bmatrix} 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)} \end {bmatrix} \ dx$

$\mathbf{\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = x^2 + \dfrac{5}{2}In | x-10|\dfrac{3}{2} In |x+2|+C}$

3. Due to the fact that the maximum words this text box can contain are 5000 words, we decided to write the solution for question 3 and upload it in an image format.

Please check to the attached image below for the solution to question number 3.

4 0

3 years ago