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Aleksandr-060686 [28]
2 years ago
10

I need to know all the answers for this homework!!!!

Chemistry
1 answer:
maw [93]2 years ago
5 0

1. 100 C

2. Point B to C is the ices heat capacity

3. During the points D to E the bonds of the water molecules build up enough kinetic energy to break their intermolecular bonds (not intra), which can lead to gas.

4. Between points D and E the energy is being released the energy required is equivalent along the line.

5. Between point E and D the water is converting to water (condensation)

6. Energy is being released 2260 j/g

7. Yes, but only under extreme volumetric pressures

8. D and E or B and C

9. Freezing (the water is also becoming less dense)

10. Melting or if water already, absorbtion of energy

11. released.

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What titrant will be used to titrate the 0. 02 m hcl phenol red solution?
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The NaOH will be used What titrant  to titrate the 0. 02 m hcl phenol red solution.

Acid-base titrations may be the most typical titrations, although there are numerous more forms as well. Take a look at this illustration where sodium hydroxide is used to titrate a sample of hydrochloric acid (HCl) (NaOH). The titrant (NaOH), which is added gradually throughout the duration of the titration, has been added to the unknown solution.

Titrants are solutions with known concentrations that are added to solutions whose concentrations must be determined. The solution for whom the concentration needs to be determined is known as a titrant as well as analyte.

Therefore, the NaOH will be used as a titrant to titrate the 0. 02 m hcl phenol red solution.

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Compare and contrast the concepts of average mass and relative mass. Which one is more accurate, and why? Why is the one you did
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Relative and average atomic mass both describe properties of an element related to its different isotopes.

Explanation:However, relative atomic mass is a standardized number that's assumed to be correct under most circumstances, while average atomic mass is only true for a specific sample.

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A similar reaction is used frequently in laboratory experiments as an indicator. Can you guess what that might be?
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In yeast, ethanol is produced from glucose under anaerobic conditions. A cell‑free yeast extract is placed in a solution that co
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0.35 milli moles of ethanol can be theoretically be produced under these conditions.

Explanation:

C_6H_{12}O_6 + 2 ADP + 2 Pi\rightarrow 2 C_2H_5OH + 2 ATP + 2 CO_2

Moles of glucose = 3.50\times 10^2 milli mole

Moles of ADP = 0.35 milli mole

Moles of Pi = 0.35 milli mole

Moles of ATP = 0.70 milli mole

As we can see that ADP and Pi are in limiting amount which means tat they are limiting reagent. So, the moles of ethanol produced will depend upon the moles of ADP and Pi.

According to reaction, 2 moles of ADP gives 2 moles of glucose.

Then 0.35 milli moles of ADp will give :

\frac{2}{2}\times 0.35 mmol=0.35 mmol of ethanol

0.35 milli moles of ethanol can be theoretically be produced under these conditions.

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