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rosijanka [135]
3 years ago
13

How many variables are you allowed to change a purpose in a experiment

Chemistry
1 answer:
evablogger [386]3 years ago
4 0
Only one. variable to get a reliable results you only have to change one.
You might be interested in
What is the halogen in period 5?? it has six letters
Misha Larkins [42]
Simple,

take a look at your periodic table, if you have it labeled look at the Halogen

Group, it includes: Flourine, Chlorine, Bromine, Iodine, and Astatine.

Now, a period on the periodic table is read from left to right, and goes

down the rows of the periodic table.

Go to Period 5, go all the way to the Halogens, what is there? 

Iodine.

Thus, your answer.
8 0
3 years ago
A student needed to make 100.0 mL of 0.20M NaOH solution. How many grams of sodium hydroxide does the student need to weigh out
GuDViN [60]

Answer:

0.08 g

Explanation:

100.0 mL = 0.10 L

Multiply the volume by the molarity to find moles.

0.10 L × 0.20 M = 0.002 mol

Convert moles to grams.

0.002 mol × 40 g/mol = 0.08 g

4 0
3 years ago
Consider the incorrectly balanced combustion equation:
Ulleksa [173]
Oxygen is balanced incorrectly.
The correct balanced equation: 2C6H6+15O2=12CO2+6H2O
6 0
2 years ago
Thomas has 235 grams of K2S in the chemistry lab. How many atoms of potassium (K) are in 235 grams of the compound?
iVinArrow [24]

The  number of atoms  of K that are in 235 g  of the compound  is

2.57 x10^24 atoms


 calculation

Step 1:  find the moles of K2S

= moles = mass/molar mass

=  235 g/110 g/mol= 2.136  moles

Step 2: multiply  2.136 moles  by no. of K atoms in K2S

= 2.136  x2 = 4.272 moles


Step 3: use the Avogadro's  law to determine number of K atoms

that is according to Avogadro's law  1 mole = 6.02 x 10^23  atoms

                                                            4.272 moles= ? atoms

by cross multiplication

= (4.272  moles x 6.02 x10^23 atoms)  / 1 mole = 2.57 x10^24 atoms

4 0
3 years ago
3 CuCl2 + 2A1 –> 2AlCl3 + 3Cu
cricket20 [7]

Answer:

aluminum

Explanation:

just did it on edge2020

6 0
3 years ago
Read 2 more answers
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