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lesya692 [45]
2 years ago
13

Perform the following operationand express the answer inscientific notation.7.00x10^5 - 5.00x10^4

Chemistry
1 answer:
11Alexandr11 [23.1K]2 years ago
3 0

Taking into account the scientific notation,  the result of the subtraction is 6.5×10⁵.

<h3>Scientific notation</h3>

First, remember that scientific notation is a quick way to represent a number using powers of base ten.

The numbers are written as a product:

a×10ⁿ

where:

  • a is a real number greater than or equal to 1 and less than 10, to which a decimal point is added after the first digit if it is a non-integer number.
  • n is an integer, which is called an exponent or an order of magnitude. Represents the number of times the comma is shifted. It is always an integer, positive if it is shifted to the left, negative if it is shifted to the right.
<h3 /><h3>Subtraction in scientific notation</h3>

You want to subtract two numbers in scientific notation. It should be noted that when the numbers to be added do not have the same base 10 exponent, the base 10 power with the highest exponent must be found. In this case, the highest exponent is 5.

Then all the values ​​are expressed as a function of the base 10 exponent with the highest exponent. In this case: 5.00×10⁴=0.500×10⁵

Taking the quantities to the same exponent, all you have to do is subtract what was previously called the number "a". In this case:

7.00×10⁵ - 0.500×10⁵= (7.00- 0.500)×10⁵= 6.5×10⁵

Finally, the result of the subtraction is 6.5×10⁵.

Learn more about scientific notation:

brainly.com/question/11403716

brainly.com/question/853571

#SPJ1

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3 years ago
How many moles of copper are present in a sample of tennantite with a mass of 2290 grams?
grin007 [14]

Answer:

               18.58 moles of Cu

Solution:

Data Given:

                  Chemical Formula of Tennantite  =  Cu₁₂As₄S₁₃

                  Mass of Cu₁₂As₄S₁₃  =  2290 g

                  M.Mass of Cu₁₂As₄S₁₃  =  1479.06 g.mol⁻¹

Step 1: Calculate Moles of Cu₁₂As₄S₁₃ as,

                               Moles  =  Mass ÷ M.Mass

Putting values,

                               Moles  =  2290 g ÷ 1479.06 g.mol⁻¹

                                Moles  =  1.548 mol

Step 2: Calculate Moles of Cu,

As,

                         1 mole of Cu₁₂As₄S₁₃ contains  =  12 moles of Cu

So,

               1.548 mol of Cu₁₂As₄S₁₃ will contain  =  X moles of Cu

Solving for X,

                     X  =  (1.548 mol × 12 mol) ÷ 1 mol

                     X  =  18.58 moles of Cu

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In the reaction below, what is the limiting reactant when 1.24 moles NH3 of reacts with 1.79 moles of NO?
kotegsom [21]

Answer:

Option 1. NO

Explanation:

The balanced equation for the reaction is given below below:

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From the balanced equation above,

4 moles of NH₃ reacted with 6 moles of NO.

Finally, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

4 moles of NH₃ reacted with 6 moles of NO.

Therefore, 1.24 moles of NH₃ will react with = (1.24 × 6)/4 = 1.86 moles of NO

From the calculation made above, we can see that a higher amount of NO (i.e 1.86 moles) than what was given (i.e 1.79 moles) is needed to react completely with 1.24 moles of NH₃.

Therefore, NO is the limiting reactant and NH₃ is the excess reactant.

Thus, the 1st option gives the correct answer to the question

6 0
3 years ago
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