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Naddik [55]
3 years ago
9

Make sure to show your answer using correct units and sig figs. (all of the

Chemistry
1 answer:
allochka39001 [22]3 years ago
3 0

Answer:

1. 84g.mol`¹

2. 342g.mol`¹

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Pls help A student studies the effect of an object's height on its amount of gravitational energy. This graph summarizes the dat
Sergeu [11.5K]

Answer:

B, as height increases gravitational energy increases

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A student places four identical cells into four different liquids. Over time which cell will look the smallest WXY or Z
marta [7]

Answer: W

Explanation:

The cell in liquid W will look the smallest out of the four because of Osmosis.

Osmosis is a process by which water molecules move from an area of relatively higher concentration of water to an area with a relatively lower concentration through a selectively permeable membrane(cell membrane).

With W being saltier than the cell, water molecules will move from the cell to liquid W to balance the concentrations inside and outside the cell which will lead to the cell in W being smaller.

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3 years ago
Combustion analysis of 1.200 g of an unknown compound containing carbon, hydrogen, and oxygen produced 2.086 g of CO2 and 1.134
timurjin [86]
<span>the empirical formula is C3H8O2 You need to determine the relative number of moles of hydrogen and carbon. So you first calculate the molar mass of CO2 and H20 Atomic weight of carbon = 12.0107 Atomic weight of hydrogen = 1.00794 Atomic weight of oxygen = 15.999 Molar mass CO2 = 12.0107 + 2 * 15.999 = 44.0087 Molar mass H2O = 2 * 1.00794 + 15.999 = 18.01488 Now calculate the number of moles of CO2 and H2O you have Moles CO2 = 2.086 g / 44.0087 g/mole = 0.0474 mole Moles H2O = 1.134 g / 18.01488 g/mole = 0.062948 mole Calculate the number of moles of carbon and hydrogen you have. Since there's 1 carbon atom per CO2 molecule, the number of moles of carbon is the same as the number of moles of CO2. But since there's 2 hydrogen atoms per molecule of H2O, The number of moles of hydrogen is double the number of moles of H2O Moles Carbon = 0.0474 Moles Hydrogen = 0.062948 * 2 = 0.125896 Now we need to determine how much oxygen is in the compound. Just take the mass of the compound and subtract the mass of carbon and hydrogen. What's left will be the mass of oxygen. Then divide that mass by the atomic weight of oxygen to get the number of moles of oxygen we have. 1.200 - 0.0474 * 12.0107 - 0.125896 * 1.00794 = 0.503797 Moles oxygen = 0.503797 / 15.999 = 0.031489 So now we have a ratio of carbon:hydrogen:oxygen of 0.0474 : 0.125896 : 0.031489 We need to find a ratio of small integers that's close to that ratio. Start by dividing everything by 0.031489 (selected because it's the smallest value) getting 1.505288 : 3.998095 : 1 The 1 for oxygen and the 3.998095 for hydrogen look close enough. But the 1.505288 for carbon doesn't work. But it looks like if we double all the numbers, we'll get something close to an integer for everything. So do so. 3.010575 : 7.996189 : 2 Now this looks good. Rounding everything to an integer gives us 3 : 8 : 2 So the empirical formula is C3H8O2</span>
5 0
3 years ago
Certain crops require a specific amount of annual rainfall to be successful. Which statement explains why coconut palm trees are
creativ13 [48]
Because there is a lot of rain, it is a tropical area and has a tropical climate.

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7 0
3 years ago
Read 2 more answers
The half-life of Erbium-165 is 10.4 hours. After 24 hours a sample has been reduced to a mass of 2 mg. What was the initial mass
Pachacha [2.7K]

Answer:

[A_0]=10\ mg

[A_t]=0.08245\ mg

Explanation:

Given that:

Half life = 10.4 hours

t_{1/2}=\frac{\ln2}{k}

Where, k is rate constant

So,  

k=\frac{\ln2}{t_{1/2}}

k=\frac{\ln2}{10.4}\ hour^{-1}

The rate constant, k = 0.06664 hour⁻¹

Time = 24 hours

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t  = 2 mg

[A_0] is the initial concentration = ?

So,  

2\ mg=[A_0]\times e^{-0.06664\times 24}

[A_0]=10\ mg

Now, time = 3 days = 3*24 hours = 72 hours ( 1 day = 24 hours)

[A_0]=10\ mg

Thus,

[A_t]=10\times e^{-0.06664\times 72}\ mg=0.08245\ mg

6 0
4 years ago
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