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3 years ago

15

The most recent treason indictment involved a U.S. citizen who was accused of turning into an operative for which of the followi

ng terrorist groups?
Question options:

The Taliban

The Shining Path

ISIS

al-Qaeda

1 answer:

likoan [24]3 years ago

3 0

The correct answer would be C isis.

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A mixture of helium and methane gases, at a total pressure of 821 mm Hg, contains 0.723 grams of helium and 3.43 grams of methan

Nookie1986 [14]

<u>Answer:</u>

<u>For 1:</u> The partial pressure of helium is 376 mmHg and that of methane gas is 445 mmHg

<u>For 2:</u> The mole fraction of nitrogen gas is 0.392 and that of carbon dioxide gas is 0.608

<u>Explanation:</u>

<u>For 1:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

<u>For helium:</u>

Given mass of helium = 0.723 g

Molar mass of helium = 4 g/mol

Putting values in equation 1, we get:

$\text{Moles of helium}=\frac{0.723g}{4g/mol}=0.181mol$

<u>For methane gas:</u>

Given mass of methane gas = 3.43 g

Molar mass of methane gas = 16 g/mol

Putting values in equation 1, we get:

$\text{Moles of methane gas}=\frac{3.43g}{16g/mol}=0.214mol$

To calculate the mole fraction , we use the equation:

$\chi_A=\frac{n_A}{n_A+n_B}$ .......(2)

To calculate the partial pressure of gas, we use the equation given by Raoult's law, which is:

$p_{A}=p_T\times \chi_{A}$ ......(3)

<u>For Helium gas:</u>

We are given:

$n_{He}=0.181mol\\n_{CH_4}=0.214mol$

Putting values in equation 2, we get:

$\chi_{He}=\frac{0.181}{0.181+0.214}=0.458$

Calculating the partial pressure by using equation 3, we get:

$p_T=821mmHg\\\\\chi_{He}=0.458$

Putting values in equation 3, we get:

$p_{He}=0.458\times 821mmHg=376mmHg$

<u>For Methane gas:</u>

We are given:

$n_{He}=0.181mol\\n_{CH_4}=0.214mol$

Putting values in equation 2, we get:

$\chi_{CH_4}=\frac{0.214}{0.181+0.214}=0.542$

Calculating the partial pressure by using equation 3, we get:

$p_T=821mmHg\\\\\chi_{CH_4}=0.542$

Putting values in equation 3, we get:

$p_{CH_4}=0.542\times 821mmHg=445mmHg$

Hence, the partial pressure of helium is 376 mmHg and that of methane gas is 445 mmHg

<u>For 2:</u>

We are given:

Partial pressure of nitrogen gas = 363 mmHg

Partial pressure of carbon dioxide gas = 564 mmHg

Total pressure = (363 + 564) mmHg = 927 mmHg

Calculating the mole fraction of the gases by using equation 3:

<u>For nitrogen gas:</u>

$363=\chi_{N_2}\times 927\\\\\chi_{N_2}=\frac{363}{927}=0.392$

<u>For carbon dioxide gas:</u>

$564=\chi_{CO_2}\times 927\\\\\chi_{CO_2}=\frac{564}{927}=0.608$

Hence, the mole fraction of nitrogen gas is 0.392 and that of carbon dioxide gas is 0.608

6 0

3 years ago

What advantage does having ultraviolet vision give bees?

nikdorinn [45]

Ultraviolet helps bee's see depth and they can see 3 dimensional, they can also see long distance. Bee's have have single lenses that helps the bee maintain stability and navigate.

Short Answer: Ultraviolet vision helps bees help detect UV flower colors

- Hope this helps!

3 0

3 years ago

When 1.008 g of hydrogen reacts with chlorine in a calorimeter containing 500.00 g water, the

jeyben [28]

The heat released by reaction : C) -8870 J

<h3>Further explanation</h3>

Given

1.008 g of hydrogen

500.00 g water

The temperature rises 25.00 °C to 29.24 °C

Required

energy required

Solution

Q absorbed by water :

Q = m.c.Δt

Q = 500 g x 4.18 J/g C x (29.24-25)

Q = 8870.08 J

The reaction to produce HCl is an exothermic reaction (releasing heat), so that Q is negative

Q water = -Q HCl = -8870.08 J

5 0

3 years ago

The movement of blood from your lungs to your heart is ______.

ruslelena [56]

Answer:

B. Pulmonary Circulation

Explanation:

Pulmonary circulation moves blood between the heart and the lungs. It transports deoxygenated blood to the lungs to absorb oxygen and release carbon dioxide. The oxygenated blood then flows back to the heart.

8 0

2 years ago

How do I set this up?

Allisa [31]

Answer: -

280mg

Explanation: -

The chemical formula is C14H18N2O5

Molar mass of the compound = 12 x 14 + 1 x 18 + 14 x 2 + 16 x 5 = 294 gram

Number of nitrogen atoms present in the formula = 2

Mass of nitrogen present= 14 x 2 = 28 gram

Thus 294 gram of the compound has 28 gram.

Hence 2.95grams of the compound has (28 gram x 2.95 gram / 294 gram)

= 0.28 gram

= 280 mg

Thus 280 mg of nitrogen is present in 2.95 grams of C14H18N2O5

4 0

3 years ago