How do I find the missing angle?
1 answer:
To find the missing angle first we need to fill in the other angles.
If we look at the 128 its on a straight line that is separated by another straight line so to get the angle on the other side of the line we need to subtract 128 from 180 which is 52.
The same goes for 160 so 180-160 = 20
And again the same for 60 so 180-60 = 120
So now that we have 2 out of 3 angles in the triangle we can figure out the final one by subtracting 120 and 20 from 180 (because theres 180 degrees in a triangle) which equals 40
Now if we look at the 40 degrees the other side is its opposite which makes it the same degree, and now we once again have 2 out of the 3 angles in a triangle so go to the triangle with 52 degrees and 40 degrees and subtract them from 180 which would be 88 degrees.
Now we subtract 88 from 180 to get the missing angle that we need (because its on another straight line thats been separated by another straight line) which equals 92
So the answer to your question is 92 degrees
If we look at the 128 its on a straight line that is separated by another straight line so to get the angle on the other side of the line we need to subtract 128 from 180 which is 52.
The same goes for 160 so 180-160 = 20
And again the same for 60 so 180-60 = 120
So now that we have 2 out of 3 angles in the triangle we can figure out the final one by subtracting 120 and 20 from 180 (because theres 180 degrees in a triangle) which equals 40
Now if we look at the 40 degrees the other side is its opposite which makes it the same degree, and now we once again have 2 out of the 3 angles in a triangle so go to the triangle with 52 degrees and 40 degrees and subtract them from 180 which would be 88 degrees.
Now we subtract 88 from 180 to get the missing angle that we need (because its on another straight line thats been separated by another straight line) which equals 92
So the answer to your question is 92 degrees
You might be interested in
Answer:
See Below.
Step-by-step explanation:
We are given that ΔAPB and ΔAQC are equilateral triangles.
And we want to prove that PC = BQ.
Since ΔAPB and ΔAQC are equilateral triangles, this means that:
Likewise:
Since they all measure 60°.
Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:
Likewise:
Since ∠QAC ≅ ∠PAB:
And by substitution:
Thus:
Then by SAS Congruence:
And by CPCTC: