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umka21 [38]
3 years ago
11

What mixed number is equal to 22/7

Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
4 0
22/7 = improper fraction
T
o change it to a mixed number do the following:

22 ÷ 7 = 3.142...7 × 3 = 21
22 - 21 = 1

3 = whole number
1 = numerator
7 = denominator

3 1/7
22/7 as a mixed number is 3 1/7. 22/7 = 3 1/7
d1i1m1o1n [39]3 years ago
3 0
3 1/7 Because there are three multiples of 7 and 1 remainder.
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In the following equations a and b are equal. which number could be substituted for both a and b to make both equations correct?
Nikitich [7]
 Considering the first equation 15 × 0 = -36 + a 
 15 × 0 = 0
therefore, -36 + a =0
In the second equation
 24 × 8 × 0 = 36 - b
Consider the LS 
24 × 8 × 0 = 0
Therefore, 36 - b = 0
we are left with the two equations,
 36 - b = 0
-36 + a = 0
then, we calculate the number that can be substituted to satisfy the two equations.
solving the equations
 b = 36, and a = 36
Therefore, 36 is the number that can be used to substitute a and b in the equations 

7 0
4 years ago
Julian has worked for a beverage company for the last five years. He currently earns $12.00 an hour and $16.00 an hour overtime
trasher [3.6K]

For the first 8 hours he makes $12.00 per hour.

$12.00 * 8 = $96.00

Now you have $128.00 = 16.00h + $96.00

Subtract 96 from each side:

32 = 16h

Divide both sides by 16:

h = 2

He worked 2 hours of overtime.

8 0
3 years ago
I need an example of ‘what is a 3rd degree polynomial with two terms’ ?
Zanzabum

Answer:Cubic polynomials are polynomials of degree three. Examples include \begin{align*}x^3+8, x^3-4x^2+3x-5\end{align*}, and so on. Notice in these examples, the largest exponent for the variable is three (3). They are all cubics

Step-by-step explanation:

3 0
3 years ago
DOES SOMEONE KNOW HOW TO DO THIS???????????????????????????????????????????
Levart [38]

Answer:

1st one is 9x-2

2nd is -3x -2

3rd one (put 1 instead of x in the given functions then calculate values and multiple )6

7 0
4 years ago
911!!! please answer this!!!
VikaD [51]

\left(\dfrac{3a^{-3}b^2}{2a^{-1}b^0}\right)^2

First some simplifying:

\left(\dfrac{3a^1b^2}{2a^3b^0}\right)^2=\left(\dfrac{3b^2}{2a^2}\right)^2=\dfrac{9b^4}{4a^4}

Then with a=-2 and b=-3, we have a^4=(-2)^4=16=4^2 and b^4=(-3)^4=81=9^2, so

\dfrac{9b^4}{4a^4}=\dfrac{9\cdot9^2}{4\cdot4^2}=\dfrac{9^3}{4^3}=\dfrac{729}{64}

7 0
3 years ago
Read 2 more answers
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