We need the length of the sides.
AB=√(2-(-2))²+(4-1)²=√16+9=√25=5; BC=√4²+0=4; CA=√0+9=3. AB+BC+CA=5+4+3=12.
Answer:
Length of XM is 5.5 units.
Step-by-step explanation:
Given △XYZ where MZ is the angle bisector of ∠YZX . we have to find the length of XM.
A triangle with vertices X, Y, and Z. Side XZ is base. A line segment drawn from Z to M bisects ∠YZX into two parts ∠YZM and ∠XZM.
YZ=7 units, XZ=11 units and YM=3.5 units
By angle bisector theorem which states that an angle bisector of an angle divides the opposite side in two segments that are proportional to the another two sides of the triangle.
Hence, 
⇒ 
⇒ MX=5.5 units.
Hence, length of XM is 5.5 units.
Answer:
x equals 3.00cm
Step-by-step explanation:
Use Pythagoras' Theorem.
a = (14x-45)
b = (16x+27)
c = (25x)
Plug in the variables above into Pythagoras' Theorem that is, a^2+b^2=c^2.
Solve the resulting quadratic equation and reject the negative answer as length is always positive.
You can prove the proofs by showing your work to prove the proofs.
Answer:
B. 45
Step-by-step explanation:
do 12×12 which is 144 then Davide it by 2 because it's a triangle then do 9×3 which is 27 then subtract that from 72 and you get 45.