Question

A young sumo wrestler decided to go on a special diet to gain weight rapidly. W(t) models the wrestler's weight (in kilograms) as a function of time t (in months). W(t)=80+5.4t
What was the wrestler's weight before his special diet?

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Answer 1

Answer:

The wrestler gains 10.8 kilograms every 2 months.

Step-by-step explanation:

The rate of change of the equation is 5.4 kilograms per month. To find the weight gain, we can multiply the rate of change by 2, the number of months. :)

Answer 2

Answer:

80kg

Step-by-step explanation:

A young sumo wrestler decided to go on a special diet to gain weight rapidly. W(t) models the wrestler's weight (in kilograms) as a function of time t (in months). W(t)=80+5.4t

What was the wrestler's weight before his special diet?

Again the function is  W(t)=80+5.4t,

We know that W is the weight while t stands for time in months

so we can start by using t at 0,3,4

when t=0

W(0)=80+5.4*0=80kg

W(3)=80+5.4*3=96.2kg

W(4)=80+5.4*3=101.6kg

so before his special diet he was 80kg