Answer:
a) E = 17.55 MeV
b) E = 18.99 MeV
c) E = 3.29 MeV
d) You can use the methods applied for the other parts to solve this, the equation is not properly written
e) E = 4.075 MeV
Explanation:
Energy Released, 

Mass of 1H, 
Mass of 2H, 
Mass of 3H, 
Mass of Helium, 
Mass of Beryllium, 
Mass of neutron, 
a) 

Energy released,

Energy released = 17.55 MeV
b) 

Energy released,

c)
+ n

Energy released,

E = 3.29 MeV(Energy is released)
d) You can use the methods applied for the other parts to solve this, the equation is not properly written
e) 


E = 4.075 MeV ( Energy is released)
Answer:
A. to cure human diseases
Explanation:
Answer:
A) 6.48 g of OF₂ at the anode.
Explanation:
The gas OF₂ can be obtained through the oxidation of F⁻ (inverse reaction of the reduction presented). The standard potential of the oxidation is the opposite of the standard potential of the reduction.
H₂O(l) + 2 F⁻(aq) → OF₂(g) + 2 H⁺(aq) + 4 e⁻ E° = -2.15 V
Oxidation takes place in the anode.
We can establish the following relations:
- 1 Faraday is the charge corresponding to 1 mole of e⁻.
- 1 mole of OF₂ is produced when 4 moles of e⁻ circulate.
- The molar mass of OF₂ is 54.0 g/mol.
The mass of OF₂ produced when 0.480 F pass through an aqueous KF solution is:

Answer: 0.53g
Explanation:
No of moles= volume ×molarity/1000
We have the volume and the molarity
Volume=4L
Molarity=1.7M
No of moles = 4×1.7/1000
No of moles= 0.0068moles
Remember also that
No of moles= mass given/molar mass
Molar mass of Al(OH)3
Al= 27
O=16
H=1
Molar mass = Al+(O+H)3
Molar mass= 27+(16+1)3
Molar mass= 27+(17)3
Molar mass = 27+51
Molar mass= 78g/mol
To get the mass
Mass given = no of moles × molar mass
Mass= 0.0068×78
Mass= 0.53g