The correct answer is A. The correct measurement for the volume of the liquid shown is 8.5 mL. If the volume of water to be read in a graduated cylinder, it is important to read it in the lower meniscus. This will be the correct reading. Due to surface tension, water attach to the walls of the glass forming a concave at the top surface.
The molar mass of CH4 is 16 g/mol.
Answer:
Pressure or Average Kinetic Energy
Explanation:
When dealing with sealed containers filled with gas, there are many variables to consider. Namely: pressure, temperature, volume, number of molecules present.
However, this question can be solved easily, without worrying too much about the other variables. Usually the case is that if there is a difference in pressure, there will be a difference in temperature, so the answer could be that both pressures must be equal.
Another way we could look at it is that the Average Kinetic Energies between the two containers have to be equal, and this will then lead to the temperatures being equal without worrying about other variables.
Answer : If a substance is the limiting reactant, then it limits the formation of products because in the reaction it is present in limited amount.
Explanation :
While observing a chemical reaction, we can tell about whether a reactant is limiting or excess.
Step 1 : first write the chemical reaction and then balanced the chemical equation.
Step 2 : convert the given masses into the moles if mass of 
is 10.5 g and molar mass of is 28 g/mole and the mass of hydrogen is 0.40 g and molar mass of hydrogen is 2 g/mole.
Step 3 : Now we have to determine the limiting reagent and excess reagent.
Now we conclude that 
is the limiting reagent and hydrogen is an excess reagent.
Hypothesis :
Limiting reagent : It is the reagent in the chemical reaction that is totally consumed when the chemical reaction is complete. Limiting reagent limits the formation of products.
Triprotic acid is a class of Arrhenius acids that are capable of donating three protons per molecule when dissociating in aqueous solutions. So the chemical reaction as described in the question, at the third equivalence point, can be show as: H3R + 3NaOH ⇒ Na3R + 3H2O, where R is the counter ion of the triprotic acid. Therefore, the ratio between the reacted acid and base at the third equivalence point is 1:3.
The moles of NaOH is 0.106M*0.0352L = 0.003731 mole. So the moles of H3R is 0.003731mole/3=0.001244mole.
The molar mass of the acid can be calculated: 0.307g/0.001244mole=247 g/mol.
