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valina [46]
3 years ago
7

Gold has a density of about 20.0g/mL this means that each milliliter has a mass of about __ grams.

Chemistry
2 answers:
qwelly [4]3 years ago
8 0

Answer:

20.0 grams

Explanation:

If the density of gold is 20.0 g/mL, then we can multiply it by 1 mLto find the weight of 1 mL of gold.

20.0\frac{grams}{mL}*1mL=20.0 grams

dimaraw [331]3 years ago
4 0

Answer:

20.0 grams

Explanation:

If the density of gold is 20.0 g/mL, then we can multiply it by 1 mLto find the weight of 1 mL of gold.

20.0\frac{grams}{mL}*1mL=20.0 grams

Explanation:

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kvv77 [185]

Geraldo can add a pollutant with slightly basic nature so he will have a solution of neutral pH of 7.

<h3>What is pH?</h3>

The pH of a solution is the negative logarithm to base ten of the hydrogen ions concentration of the solution.

The pH of 6.5 means that the solution is acidic.

By adding a pollutant which is slightly basic in nature, Geraldo will have a solution of neutral pH which is a pH of 7.

Learn more about pH at: brainly.com/question/24595796

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boyakko [2]
Numbers 2 is your answer
5 0
3 years ago
3) The mass of a piece silver is 10.5 g. If a sample of pure silver has a volume of 13 cm3, what is the
lakkis [162]

Answer:

<h3>The answer is 0.81 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass of metal = 10.5 g

volume = 13 cm³

We have

density =  \frac{10.5}{13}  \\  = 0.8076923...

We have the final answer as

<h3>0.81 g/cm³</h3>

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2 years ago
How many moles of iron(lll) sulfide, Fe2S3, would be produced from the complete reaction of 449 g iron(lll) bromide, FeBr3?
SpyIntel [72]

Answer:

158.004 Grams of Fe2S3

Explanation:

iron(lll) sulfide = Fe2S3 = Molar mass: 207.9 g/mol

iron(lll) bromide = FeBr3 = Molar mass: 295.56 g/mol

Since we don't have the chemical equation we will have to make one I guess.

2 FeBr3 + 3 Na2S -----> 6 NaBr + Fe2S3

449 g iron(lll) bromide = FeBr3

So we have 449/295.56 = moles of FeBr3 = 1.52 Moles

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So we need 0.76 moles of Fe2S3

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7 0
3 years ago
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