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maxonik [38]
3 years ago
6

1.Let's say you could see inside of the nucleus of a Silver atom and inside the nucleus of a Cobalt atom. How would they look di

fferent?
2.If a substance has no (or almost no) likelihood of undergoing a chemical reaction with another element it is said to be:
a.Ionized
b.Malleable
c.Reactive
d.Inert
e.An Isotope

3. Evaluate this sentence and explain why it is incorrect:
“Neon came into contact with Iron and the reaction was very explosive.”

4. Mr. Carney does and experiment. He weighs himself. He weighs 210 lbs. He then runs 15 miles. Then weighs himself. He now weighs 200 lbs.
Explain the conservation of mass using this experiment as your example.
NEED ANSWERS NOW DUE TODAY
Chemistry
1 answer:
disa [49]3 years ago
8 0
Answers:
1. A silver atom would have 47 protons and more neutrons than a cobalt atom and a cobalt atom would only have 27 protons and less neutrons than a silver atom.

2. D. Inert Inert means non-reactive.

3. Neon gas is a Nobel gas on the right side of the periodic table so it is an inert gas and does not react with iron.

4. Mass is neither created or destroyed so as Mr. Carney ran carbon in his body left as carbon dioxide. So the 10 lbs he lost left his body as CO2 through the lungs.
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Un buzo que nada en las profundidades despide pequeñas burbujas de aire¿Aumenta disminuye o permanece igual el tamaño de las bur
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Answer:

Al ascender las burbujas van aumentando de tamaño.

Explanation:

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Ahora, a medida que las burbujas suben a la superficie, la presión que sufren estas (Presión debido al agua), es menor conforme van ascendiendo debido a la ley de Boyle: A medida que la presión aumenta, el volumen va disminuyendo.

Esto significa que al ascender las burbujas van aumentando de tamaño debido a que la presión que sufren estas es menor que cuando están a mayores profundidades.

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3 years ago
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goldenfox [79]

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Solar panels and solar cells.

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5 0
4 years ago
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A chemist forms 16.6 g of potassium iodide by combining 3.9 g of potassium with 12.7 g of iodine. Show that these results are co
bezimeni [28]
3.9 g + 12.7 g = 16.6 g

The sum of the masses of potassium and iodine equals the mass of the product, potassium iodide. The results are consistent with he law of conservation of mass.


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Sabendo que A Densidade do Metal De Chumbo e 11,3/cm3
a_sh-v [17]
Sabendo que A Densidade do Metal De Chumbo e 11,3/cm3 means Knowing that the density of lead Metal and 11,3/cm3.
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4 years ago
Answer these please ASAP need help no idea how to do these
STALIN [3.7K]

Answer:

Explanation:

Cu:

Number of moles = Mass / molar masa

2 mol = mass / 64 g/mol

Mass = 128 g

Mg:

Number of moles = Mass / molar masa

0.5 mol = mass / 24 g/mol

Mass =  g

Cl₂:

Number of moles = Mass / molar masa

Number of moles  = 35.5 g / 24 g/mol

Number of moles = 852 mol

H₂:

Number of moles = Mass / molar mass

8 mol  = Mass / 2 g/mol

Mass =  16 g

P₄:

Number of moles = Mass / molar masa

2 mol  =  mass / 124 g/mol

Mass = 248 g

O₃:

Number of moles = Mass / molar masa

Number of moles  = 1.6 g /48  g/mol

Number of moles = 0.033 mol

H₂O

Number of moles = Mass / molar masa

Number of moles  = 54 g / 18 g/mol

Number of moles = 3 mol

CO₂

Number of moles = Mass / molar masa

2 mol  =  mass / 124 g/mol

Mass = 248 g

NH₃

Number of moles = Mass / molar masa

Number of moles  = 8.5 g / 17 g/mol

Number of moles = 0.5 mol

CaCO₃

Number of moles = Mass / molar masa

Number of moles  = 100 g / 100 g/mol

Number of moles = 1 mol

a)

Given data:

Mass of iron(III)oxide needed = ?

Mass of iron produced = 100 g

Solution:

Chemical equation:

F₂O₃ + 3CO    →    2Fe  + 3CO₂

Number of moles of iron:

Number of moles = mass/ molar mass

Number of moles = 100 g/ 56 g/mol

Number of moles = 1.78 mol

Now we compare the moles of iron with iron oxide.

                        Fe          :           F₂O₃                

                           2          :             1

                          1.78       :        1/2×1.78 = 0.89 mol

Mass of  F₂O₃:

Mass = number of moles × molar mass

Mass = 0.89 mol × 159.69 g/mol

Mass = 142.124 g

100 g of iron is 1.78 moles of Fe, so 0.89 moles of F₂O₃ are needed, or 142.124 g of iron(III) oxide.

b)

Given data:

Number of moles of Al = 0.05 mol

Mass of iodine = 26 g

Limiting reactant = ?

Solution:

Chemical equation:

2Al + 3I₂   →  2AlI₃

Number of moles of iodine = 26 g/ 254 g/mol

Number of moles of iodine = 0.1 mol

Now we will compare the moles of Al and I₂ with AlI₃.

                          Al            :         AlI₃    

                          2             :           2

                         0.05         :        0.05

                           I₂            :         AlI₃

                           3            :          2

                         0.1           :           2/3×0.1 = 0.067

Number of moles of AlI₃ produced by Al are less so it will limiting reactant.

Mass of AlI₃:                            

Mass = number of moles × molar mass

Mass = 0.05 mol × 408 g/mol

Mass = 20.4 g

26 g of iodine is 0.1 moles. From the equation, this will react with 2 moles of Al. So the limiting reactant is Al.

c)

Given data:

Mass of lead = 6.21 g

Mass of lead oxide = 6.85 g

Equation of reaction = ?

Solution:

Chemical equation:

2Pb + O₂   → 2PbO

Number of moles of lead = mass / molar mass

Number of moles = 6.21 g/ 207 g/mol

Number of moles = 0.03 mol

Number of moles of lead oxide = mass / molar mass

Number of moles = 6.85 g/ 223 g/mol

Number of moles = 0.031 mol

Now we will compare the moles of oxygen with lead and lead oxide.

               Pb         :        O₂

                2          :         1

               0.03     :      1/2×0.03 = 0.015 mol

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 0.015 mol × 32 g/mol

Mass =  0.48 g

The mass of oxygen that took part in equation was 0.48 g. which is 0.015 moles of oxygen. The number of moles of Pb in 6.21 g of lead is 0.03 moles. So the balance equation is

2Pb + O₂   → 2PbO

   

6 0
3 years ago
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