Initial momentum = 0.15 kg * (-5 m/s) = - 0.75 N*s
final momentum = 0.15 * ( 3 m/s) = 0.45 N*s
Change in momentum = final momentum - initial momentun =
= 0.45N*s - (- 0.75N*s) = 1.2 N*s
Answer: 1.2 N*s
Answer:
The gravitational potential energy of the man
= mass of the man(m) × gravitational acceleration(g) × height (h)
80 Kg × 9.8 m/s^2 × 60 m
80 × 9.8 x 60 ( kg ×m^2/s^2)
47040 Joules (ans)
Hope it helps
In the opposite figure, the work done by the force F to push the box upwards from the ground to the top of the inclined plane is 600 J.Option c is correct.
<h3>What is work done?</h3>
Work done is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.
The displacement value from the triangle is;

The work done is found as ;

The force F in the opposing figure does 600 J of effort to lift the box from the ground to the top of the inclined plane.
Hence option c is correct.
To learn more about the work done refer to the link;
brainly.com/question/3902440
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The related concepts to solve this problem is the Glide Ratio. This can be defined as the product between the height of fall and the lift-to-drag ratio. Mathematically, this expression can be written as,

Replacing,


Converting this units to miles.


Therefore the glide in terms of distance measured along the ground is 7.2916miles