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Vlad [161]
4 years ago
11

Please answer!!! I’m desperate

Physics
1 answer:
rodikova [14]4 years ago
8 0

a is the answer hope this helps

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A billiard ball with a mass of 0.15 kg has a velocity of 5 m/s. It strikes the bumper of the table perpendicularly and bounces s
Marianna [84]
Initial momentum = 0.15 kg * (-5 m/s) = - 0.75 N*s

final momentum = 0.15 * ( 3 m/s) =  0.45 N*s

Change in momentum = final momentum - initial momentun =

= 0.45N*s - (- 0.75N*s) =  1.2 N*s

Answer:  1.2 N*s


5 0
3 years ago
When you heat ice on a hot stove, the ice melts. what is happening during this process?
masya89 [10]
Heat energy is being transferred
5 0
3 years ago
Read 2 more answers
An 80kg person falls 60 m off of a waterfall. What is her GPE?
ElenaW [278]

Answer:

The gravitational potential energy of the man

= mass of the man(m) × gravitational acceleration(g) × height (h)

80 Kg × 9.8 m/s^2 × 60 m

80 × 9.8 x 60 ( kg ×m^2/s^2)

47040 Joules (ans)

Hope it helps

4 0
3 years ago
In the opposite figure, the work done by the force F to push the box upwards from the ground to the top of the inclined plane is
goldfiish [28.3K]

In the opposite figure, the work done by the force F to push the box upwards from the ground to the top of the inclined plane is 600 J.Option c is correct.

<h3>What is work done?</h3>

Work done is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.

The displacement value from the triangle is;

\rm sin 30^0 = \frac{P}{H} \\\\ H=S =\frac{3 \ m}{sin 30^0} \\\\ S = 6\ m

The work done is found as ;

\rm W= Fd \\\\ W = 100  \ N \times 6 \\\\ W= 600 \ J

The force F in the opposing figure does 600 J of effort to lift the box from the ground to the top of the inclined plane.

Hence option c is correct.

To learn more about the work done refer to the link;

brainly.com/question/3902440

#SPJ1

4 0
2 years ago
The maximum lift-to-drag ratio of the World War I Sopwith Camel was 7.7. If the aircraft is in flight at 5000 ft when the engine
andre [41]

The related concepts to solve this problem is the Glide Ratio. This can be defined as the product between the height of fall and the lift-to-drag ratio. Mathematically, this expression can be written as,

R = h (\frac{L}{D})_{max}

Replacing,

R = 5000ft (7.7)

R = 38500ft

Converting this units to miles.

R = 38500ft (\frac{1mile}{5280ft})

R = 7.2916miles

Therefore the glide in terms of distance measured along the ground is 7.2916miles

3 0
4 years ago
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