Answer:
The magnitude of the force required to move the electron through the given field is 2.203 N
Explanation:
Given;
The field strength of the electron, E = 1.375 x 10¹⁹ N/C
charge of electron, q = 1.602 x 10⁻¹⁹ C
The magnitude of the force required to move the electron through the given field is calculated as follows;
F = Eq
F = (1.375 x 10¹⁹ N/C) (1.602 x 10⁻¹⁹ C)
F = 2.203 N
Therefore, the magnitude of the force required to move the electron through the given field is 2.203 N
Answer:
PE = (|accepted value – experimental value| \ accepted value) x 100%
Explanation:
Answer:
The value is 
Explanation:
From the question we are told that
The power rating of the stove is 
The duration of its use everyday is
The rating of the light bulbs is 
The number is 
The power rating of the total bulb is 
The duration of its use everyday is 
The power rating of miscellaneous appliance 
The duration of its use everyday is 
The power rating of hot water 
The duration of its use everyday is 
Generally the total electrical energy used in 1 month is mathematically represented as

=> 
=> 
=> 
Generally the monthly electricity bill is mathematically represented as

=> 
Answer:
velocity = 1527.52 ft/s
Acceleration = 80.13 ft/s²
Explanation:
We are given;
Radius of rotation; r = 32,700 ft
Radial acceleration; a_r = r¨ = 85 ft/s²
Angular velocity; ω = θ˙˙ = 0.019 rad/s
Also, angle θ reaches 66°
So, velocity of the rocket for the given position will be;
v = rθ˙˙/cos θ
so, v = 32700 × 0.019/ cos 66
v = 1527.52 ft/s
Acceleration is given by the formula ;
a = a_r/sinθ
For the given position,
a_r = r¨ - r(θ˙˙)²
Thus,
a = (r¨ - r(θ˙˙)²)/sinθ
Plugging in the relevant values, we obtain;
a = (85 - 32700(0.019)²)/sin66
a = (85 - 11.8047)/0.9135
a = 80.13 ft/s²
Answer:
0.37 m
Explanation:
The angular frequency, ω, of a loaded spring is related to the period, T, by

The maximum velocity of the oscillation occurs at the equilibrium point and is given by

A is the amplitude or maximum displacement from the equilibrium.

From the the question, T = 0.58 and A = 25 cm = 0.25 m. Taking π as 3.142,

To determine the height we reached, we consider the beginning of the vertical motion as the equilibrium point with velocity, v. Since it is against gravity, acceleration of gravity is negative. At maximum height, the final velocity is 0 m/s. We use the equation

is the final velocity,
is the initial velocity (same as v above), a is acceleration of gravity and h is the height.

