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spin [16.1K]
4 years ago
15

How long would it take for a rock falling 97.2 m/s to reach the ground from 100 meters

Physics
1 answer:
mote1985 [20]4 years ago
5 0

Answer;

velocity(v) = 97.2 m/s ,

distance (S) = 100 m

determine time(t) = ?

  We know that,

               distance (S) = velocity(v) × time(t)

           So,      time (t) = distance ÷ velocity

                                   = 100 ÷ 97.2

                              <em>   t = 1.02 sec.</em>

<em>I hope this will help you.</em>

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Harry is reading an online summary of the law of reflection. The site states that after light hits a mirror, the angle of reflec
tatiyna

'The normal is a line perpendicular to the surface of the mirror'.This is the correct statement that corrects an error on the site.

<h3>What is the law of reflection?</h3>

The law of reflection specifies that upon reflection from a downy surface, the slope of the reflected ray is similar to the slope of the incident ray.

The reflected ray is consistently in the plane determined by the incident ray and perpendicular to the surface at the point of reference of the incident ray.

When the light rays descend on the smooth surface, the angle of reflection is similar to the angle of incidence, also the incident ray, the reflected ray, and the normal to the surface all lie in a similar plane.

Hence 'The normal is a line perpendicular to the surface of the mirror'.This is the correct statement that corrects an error on the site

To learn more about the law of reflection refer to the link;

brainly.com/question/12029226

5 0
2 years ago
Read 2 more answers
An object with velocity 141 ft/s has a kinetic energy of 1558.71 ft∙lbf, on a planet whose gravity is 31.5 ft/s2. What is its
Sidana [21]

Answer:

The mass of the object is 5.045 lbm.

Explanation:

Given;

kinetic energy of the object, K.E = 1558.71 ft.lbf

velocity of the object, V = 141 ft/s

The kinetic energy of the object is calculated as;

K.E = \frac{1}{2} mV^2\\\\mV^2 = 2K.E\\\\m = \frac{2K.E}{V^2} \\\\1 \ lbf = 32.174 \ lbm.ft/s^2\\\\m  = \frac{2 \ \times \ 1558.71 \ ft.lbf \ \times \ 32.174 \ lbm.ft/s^2 }{(141 \ ft/s)2 \ \  \times \ \ \ \ 1   \ lbf\ }

m  = \frac{(2 \ \times \ 1558.71  \ \times \ 32.174) \ lbm.ft^2/s^2 }{(141 )^2\ ft^2/s^2 }\\\\m = \frac{(2 \ \times \ 1558.71  \ \times \ 32.174) \ lbm }{(141 )^2 }\\\\m = 5.045 \ lbm

Therefore, the mass of the object is 5.045 lbm.

6 0
3 years ago
What is the mass of an object that weighs 686N on Earth?
Oxana [17]

Answer:

70 kg is the mass of the object

Explanation:

This question can be solved with this simple formula:

Weight force = mass . gravity

686 N = mass . 9.8 m/s²

686 N /  9.8 m/s² = mass → 70 kg

Note → 1N = 1 kg . m / s²

8 0
3 years ago
Friction is defined as *
den301095 [7]

Answer:

O a force that opposes motion

5 0
3 years ago
A box has a momentum of
Kipish [7]

Answer:

67.9 kg*m/s

Explanation:

Pi = 38 kgm/s

F = 88.3N and ∆t = 0.338s

Final momentum Pf = Pi + F∆t = 38 + (88.3)(0.338) = 38 + 29.8454

=) Pf = 67.8454 kgm/s = 67.85kg*m/s

Your answer is 67.9kg*m/s with three significant figures

hope this helps your troubles!

6 0
3 years ago
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