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3 years ago

How does online gaming affect the health of the student

Physics

2 answers:

ale4655 [162]3 years ago

8 0

Answer:

because we more see th online gaming and not eat food and playing that game all the time so it effect the health

hope you like it please follow me

Kruka [31]3 years ago

3 0

Click at the above pic and the ans will appear.

Hope it helps :)

You might be interested in

How does the amount of energy coming from the energy source (low vs. high) affect the amount of electrical energy created?

Ugo [173]

Answer:

The environmental problems directly related to energy production and Electricity is a secondary energy source that is generated producedfrom primary energy sources:

hope that helps im new so have a good day (:

3 0

2 years ago

A 50.0-kg block is being pulled up a 13.0° slope by a force of 250 N which is parallel to the slope, but the block does not slid

Elan Coil [88]

Weight of block, Wb = mass*gravity = 50*9.8 = 490 N

Since block is being pulled up by a 13-degree slope

Therefore, Force which is acting parallel to the slop:

F p =490 Sin $13^{0}$ = 110.2N

Force which is acting perpendicular to the slope:

Fv =490 Cos $13^{0}$ = 477.4 N

Net force can be given as follows:

F n = (250 - 110.2 - 0.2*477.4) N

Fn=44.3N

Now acceleration is given by the ratio of force to mass

a = Fn/m

=44.3/50 = 0.89 ms^-2

8 0

3 years ago

Given vectors D (3.00 m, 315 degrees wrt x-axis) and E (4.50 m, 53.0 degrees wrt x-axis), find the resultant R= D + E. (a) Write

Eva8 [605]

Answer:

R = ( 4.831 m , 1.469 m )

Magnitude of R = 5.049 m

Direction of R relative to the x axis= 16°54'33'

Explanation:

Knowing the magnitude and directions relative to the x axis, we can find the Cartesian representation of the vectors using the formula

$\vec{A}= | \vec{A} | \ ( \ cos(\theta) \ , \ sin (\theta) \ )$

where $| \vec{A} |$ its the magnitude and θ.

So, for our vectors, we will have:

$\vec{D}= 3.00 m \ ( \ cos(315) \ , \ sin (315) \ )$

$\vec{D}= ( 2.121 m , -2.121 m )$

and

$\vec{E}= 4.50 m \ ( \ cos(53.0) \ , \ sin (53.0) \ )$

$\vec{E}= ( 2.71 m , 3.59 m )$

Now, we can take the sum of the vectors

$\vec{R} = \vec{D} + \vec{E}$

$\vec{R} = ( 2.121 \ m , -2.121 \ m ) + ( 2.71 \ m , 3.59 \ m )$

$\vec{R} = ( 2.121 \ m + 2.71 \ m , -2.121 \ m + 3.59 \ m )$

$\vec{R} = ( 4.831 \ m , 1.469 \ m )$

This is R in Cartesian representation, now, to find the magnitude we can use the Pythagorean theorem

$|\vec{R}| = \sqrt{R_x^2 + R_y^2}$

$|\vec{R}| = \sqrt{(4.831 m)^2 + (1.469 m)^2}$

$|\vec{R}| = \sqrt{23.338 m^2 + 2.158 m^2}$

$|\vec{R}| = \sqrt{25.496 m^2}$

$|\vec{R}| = 5.049 m$

To find the direction, we can use

$\theta = arctan(\frac{R_y}{R_x})$

$\theta = arctan(\frac{1.469 \ m}{4.831 \ m})$

$\theta = arctan(0.304)$

$\theta = 16\°54'33''$

As we are in the first quadrant, this is relative to the x axis.

3 0

3 years ago

You throw a rock upwards; it rises and then falls back down. We know that the acceleration due to gravity is 9.8 m/sec2 near the

Leokris [45]

Answer:

Acceleration = 9.8 m/sec2

Explanation:

We know that the acceleration due to gravity is 9.8 m/sec2 near the surface of earth.

Remember that the gravity is always affecting everything on earth at every instant, even the rock at the very top of it's trajectory. It doesn't mind if the velocity is zero for an instant or if there's air resistance, the gravity force is there, and always aims towards the center of the earth.

So for all the trajectory of the rock, gravity is 9.8 m/sec2

6 0

3 years ago

True or False? In the quark era, it was so hot that matter and

Eva8 [605]

Answer:

False

Explanation:

Great educated guess energy and matter is different

8 0

4 years ago