Answer:
1/38 of Kelly's beads are blue.
Step-by-step explanation:
four eighths = 1/2 or 1 half
1/2 of them are red.
18 white beads, so number of red beads have to be bigger than 18 since she has blue beads too.
So, we can just estimate she has just one blue bead so then the 18 whites become 19 so we need to make red beads the same amount as it is half of the total.
The total is 38 since 19 + 19 = 38 (total beads)
So, blue is 1/38 as a fraction.
Hope this helps. :)
Answer:
i
Step-by-step explanation:
Answer:
The worth of the car after 6 years is £2,134.82
Step-by-step explanation:
The amount at which Dan buys the car, PV = £2200
The rate at which the car depreciates, r = -0.5%
The car's worth, 'FV', in 6 years is given as follows;

Where;
r = The depreciation rate (negative) = -0.5%
FV = The future value of the asset
PV = The present value pf the asset = £2200
n = The number of years (depreciating) = 6
By plugging in the values, we get;

The amount the car will be worth which is its future value, FV after 6 years is FV ≈ £2,134.82 (after rounding to the nearest penny (hundredth))
Answer:
Solutions will be unreal
Step-by-step explanation:
Given the quadratic equation ax^2+bx+c
The discriminant of the function determines its nature of its root
Discriminant D = b^2-4ac
If D <0, it shows that the roots of the equation will be a complex value. since D is less than 0 and the square root of a negative number does not exist. Hence, the solutions will be unreal
4w⁹ -2w⁹
= (4-2)w⁹ . . . . . distributive property, or "collecting terms"
= 2w⁹
_____
In plain text, a caret (^) is used to identify an exponent. w⁹ = w^9. If the exponent has any arithmetic, you need parentheses around it. w^(8+1)