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oksano4ka [1.4K]
3 years ago
15

Our galaxy is what type of galaxy? spiral irregular cylinder elliptical

Physics
2 answers:
DaniilM [7]3 years ago
8 0
Its called a spiral galaxy... our galaxy is an spiral galaxy, case its apart of the milky way making it spiral 
wlad13 [49]3 years ago
3 0
Our galaxy is Milky way. it is spiral

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An ideal gas is enclosed in a cylinder that has a movable piston on top. The piston has a mass m and an area A and is free to sl
elena-14-01-66 [18.8K]

Answer:

Explanation:

Given mass of piston \left ( m\right )

no. of moles =n

Given Pressure remains same

Temperature changes from T_1 to T_2

Work done\left ( W\right ) is given by=\int_{V_1}^{V_2}PdV

W=P\left ( V_2-V_1\right )

also PV_1=nRT_1

PV_2=nRT_2

W=nR\left ( T_2-T_1\right )

4 0
3 years ago
Why is the scientific method described as cyclic?
Troyanec [42]
Because the scientific method can go around in a circle as many times as neccisary to get the results you need
8 0
3 years ago
Why is the weight of an object more on Earth than the Moon
Ann [662]

Answer:

Due to gravity on the earth but on moon there is 1/6th of the gravity than on earth. Since the acceleration of gravity Is lesser in moon and weight is constant, the weight of an object is lesser on the surface of the moon.

Explanation:

4 0
3 years ago
What's another name for a longitudinal wave?
BlackZzzverrR [31]

Answer: Mechanical longitudinal waves are also called compressional or compression waves, because they produce compression and rarefaction when traveling through a medium, and pressure waves, because they produce increases and decreases in pressure.

Explanation:

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7 0
3 years ago
Read 2 more answers
You throw a rock straight up from the edge of a cliff. It leaves your hand at time t = 0 moving at 13.0 m/s. Air resistance can
Zarrin [17]

Answer:

0.36s, 2.3s

Explanation:

Let gravitational acceleration g = 9.81 m/s2. And let the throwing point as the ground 0 for the upward motion. The equation of motion for the rock leaving your hand can be written as the following:

s = v_0t + gt^2/2

where s = 4 m is the position at 4m above your hand. v_0 = 13 m/s is the initial speed of the rock when it leaves your hand. g = -9.81m/s2 is the deceleration because it's in the downward direction. And t it the time(s) it take to get to 4m, which we are looking for

4 = 13t - 9.81t^2/2

4.905 t^2 - 13t + 4 = 0

t= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

t= \frac{13\pm \sqrt{(-13)^2 - 4*(4.905)*(4)}}{2*(4.905)}

t= \frac{13\pm9.51}{9.81}

t = 2.3 or t = 0.36

7 0
4 years ago
Read 2 more answers
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