So far, since you moved into the apartment until the end of this much of the story, you haven't done ANY work on the dresser yet.
I'll admit that you pushed, groaned and grunted, sweated and strained plenty. You're physically and mentally exhausted, you're not interested in the dresser at the moment, and right now you just want to snappa cappa brew, crash on the couch, and watch cartoons on TV. But if you've done your Physics homework, you know you haven't technically done any <u><em>work</em></u> yet.
In Physics, "Work" is the product of Force times Distance.
Since the dresser hasn't budged yet, the Distahce is zero. So no matter how great the Force may be, it's multiplied by zero, so the <em>Work is zero</em>.
Both matter and light have been demonstrated to exhibit wave-like and particle-like behavior.
Light as a wave: light can diffract & refract
Light as a particle: photoelectric effect, Compton scattering
Matter as a wave: Davisson-Germer experiment
Matter as a particle: find a picture of any kinematics problem in a high school physics textbook
Choice D
To solve this problem we will calculate the total volume of inhaled and exhaled water. From the ideal gas equation we will find the total number of moles of water.
An athlete at high performance inhales 4.0L of air at 1atm and 298K.
The inhaled and exhaled air contain 0.5% and 6.2% by volume of water, respectively.
During inhalation, volume of water taken is


During exhalation, volume of water expelled is


During 40 breathes, total volume of water taken is

During 40 breathes, total volume of water expelled out is

Therefore resultant volume of water expelled out from the lung is

From the body through the lung we have that

Here,
P = Pressure
R= Gas ideal constant
T= Temperature
V = Volume
Replacing,


Therefore the moles of water per minute are expelled from the body through the lungs is 0.373mol/min
Answer:
La fuerza que se ejerce entre las dos cargas es 2880 N.
Explanation:
La ley de Coulomb indica que los cuerpos cargados sufren una fuerza atractiva o repulsiva al acercarse. La fuerza es atractiva si las cargas son del signo opuesto y repulsión si son del mismo signo. El valor de la fuerza es proporcional al producto del valor de sus cargas e inversamente proporcional al cuadrado de la distancia que los separa. Esto se expresa matemáticamente como:

donde:
- F es la fuerza eléctrica de atracción o repulsión. Se mide en Newtons (N).
- Q y q son los valores de las dos cargas puntuales. Se miden en culombios (C).
- r es el valor de la distancia que los separa. Se mide en metros (m).
- k es una constante de proporcionalidad llamada constante de la ley de Coulomb.
En este caso:
- F= ?
- Q= 4*10⁻⁵ C
- q= 2*10⁻⁵ C
- r= 0.05 m
- k= 9*10⁹

Reemplazando:

F= 2880 N
<u><em>La fuerza que se ejerce entre las dos cargas es 2880 N.</em></u>
Answer:
the second one
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