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miskamm [114]
3 years ago
12

Why is the weight of an object more on Earth than the Moon

Physics
1 answer:
Ann [662]3 years ago
4 0

Answer:

Due to gravity on the earth but on moon there is 1/6th of the gravity than on earth. Since the acceleration of gravity Is lesser in moon and weight is constant, the weight of an object is lesser on the surface of the moon.

Explanation:

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Water is flowing in a fire hose with a velocity of 1.0 m/s and a pressure of 200000 Pa. At the nozzle the pressure decreases to
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Answer:

The velocity is v_n  =14.09 \ m/s

Explanation:

From the question we are told that

    The velocity of the water in the pipe is  v_i =  1.0 \ m/s

     The pressure inside the pipe  is  P_i  = 200000 \ Pa

      The pressure at the nozzle is  P_n  =  101300 \ Pa

       The density of water is  \rho  =  1000 \ kg / m^3

      For the height h_1 = h_2 = h

where  h_1 is height of water in the pipe

  and  h_2 is height of water at the nozzle

Generally Bernoulli equation is represented as

       \frac{1}{2} \rho * v_i ^2 + \rho * g * h_1 +  P_i =  \frac{1}{2} \rho v_n ^2 + \rho * g* h_2 + P_n

=>   \frac{1}{2} \rho * v_i ^2 + \rho * g * h +  P_1 =  \frac{1}{2} \rho v_n ^2 + \rho * g* h + P_2

Where v_n is the velocity of the water at the nozzle

Now  making  v_n  the subject

            v_n  =  \sqrt{\frac{2}{\rho} [ P_i - Pn + \frac{1}{2} \rho v_i^2}

substituting values

            v_n  =  \sqrt{\frac{2}{1000} [ 200000 - 101300 + \frac{1}{2} (1000 * (1.0)^2)}

           v_n  =14.09 \ m/s

     

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Answer:

r=5.278\times 10^{-4}\ m

Explanation:

Given that:

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KE= \frac{1}{2} m.v^2

1.92\times 10^{-19}=0.5\times 9.1\times 10^{-31}\times v^2

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v=6.496\times 10^6\ m.s^{-1}

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