2.4 written in simplest form
1 answer:
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Answer:
a. H0 : p ≤ 0.11 Ha : p >0.11 ( one tailed test )
d. z= 1.3322
Step-by-step explanation:
We formulate our hypothesis as
a. H0 : p ≤ 0.11 Ha : p >0.11 ( one tailed test )
According to the given conditions
p`= 31/225= 0.1378
np`= 225 > 5
n q` = n (1-p`) = 225 ( 1- 31/225)= 193.995> 5
p = 0.4 x= 31 and n 225
c. Using the test statistic
z= p`- p / √pq/n
d. Putting the values
z= 0.1378- 0.11/ √0.11*0.89/225
z= 0.1378- 0.11/ √0.0979/225
z= 0.1378- 0.11/ 0.02085
z= 1.3322
at 5% significance level the z- value is ± 1.645 for one tailed test
The calculated value falls in the critical region so we reject our null hypothesis H0 : p ≤ 0.11 and accept Ha : p >0.11 and conclude that the data indicates that the 11% of the world's population is left-handed.
The rejection region is attached.
The P- value is calculated by finding the corresponding value of the probability of z from the z - table and subtracting it from 1.
which appears to be 0.95 and subtracting from 1 gives 0.04998
Answer:
1) For each value of x, a value of y is increased by 5.
x = 0, y = 5
x = 1, y = 10
x = 2, y = 15
x = 3, y = 20
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2) For each two values of x, a value of y is increased by 10.
x = 0, y = -2
x = 2, y = 8
x = 4, y = 18
x = 6, y = 28
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3)
x = 0, y = 1
x = 1, y =
x = 5, y = 3
x = 10, y = 5
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4)
x = 0, y = 2
x = 1, y = 17
x = 2, y = 32
x = 5, y = 77
Step-by-step explanation:
This is as easy as replacing x for the actual value show on the table.
1)
When x = 0, y = ?
When x = 1, y = ?
When x = 2, y = ?
When x = 3, y = ?
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2)
When x = 0, y = ?
When x = 2, y = ?
When x = 4, y = ?
When x = 6, y = ?
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3)
When x = 0, y = ?
When x = 1, y = ?
When x = 5, y = ?
When x = 10, y = ?
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4)
When x = 0, y = ?
When x = 1, y = ?
When x = 2, y = ?
When x = 5, y = ?