Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)
If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.
On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.
For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.
Then the range of F(x) is the interval [-π, π].
Add all them up. 5+8+2 = 15
How many yellows? 8/15 = 0.533 ~~ 53%
Answer:
1,2,3,
Step-by-step explanation:
I GOT THE ANSWER WRONG AND IT TOLD ME THE CORRECT ANSWER
Independent, x-coordinate, input, domain.
Dependent, y-coordinate, output, range.
Domain: {0.5, 1, 4, 6, 8}
Range: {1, 1.5, 10, 12, 18}
