All categories

3 years ago

A 1.5m wire carries a 2 A current when a potential difference of 59 V is applied. What is the resistance of the wire?

Physics

1 answer:

lisabon 2012 [21]3 years ago

6 0

We can use the relation of ohm's law to find out the resistance of wire

$V = i R$

given that

V = 59 volts

i = 2 A

now as per above formula

$59 = 2 * R$

$R = 29.5 ohm$

So resistance of wire is 29.5 ohm.

You might be interested in

An example of an atom that has no change is one that has A. 1 proton, 2 electrons, and 3 neutrons B. 3 protons,2 electrons, and

Vikki [24]

Your question asks which is an example of an atom that has no change, or charge.

Your answer would be C). 2 protons, 2 electrons, and 1 neutron

These atoms would be known as a neutral atom.

In order for an atom to be neutral, it must have the same amount of protons and electrons.

We know that Protons are positive

We also know that Electrons are negative

In order for the atom to be neutral, they must have an equal amount of protons and neutrons to "cancel out"

In answer choice C, you would see that there are 2 protons and 2 electrons.

2- 0 = 0, in which allows this atom to be neutral.

Therefore, answer choice C. 2 protons, 2 electrons, and 1 neutron would be your answer.

4 0

3 years ago

Read 2 more answers

Eric has a mass of 70 . He is standing on a scale in an elevator that is accelerating downward at 1.7 . What is the approximate

pychu [463]

Answer:

Explanation:

The value the scale shows is the reaction force to the normal force (they are equal by Newton's 3rd Law) that the scale exerts on Eric.

The forces on Eric are his weight (downward) and this normal force (upward), so we can write the net force over him as (also using Newton's 2nd Law):

$F=W-N=ma$

which means

$N=W-ma=mg-ma=m(g-a)$

and for our values this is:

$N=mg-ma=(70kg)(9.8m/s^2-1.7m/s^2)=567N$

5 0

3 years ago

what type of energy appears when a gymnast jumps on to a spring board? Question is on energy stores!Thanks

Brrunno [24]

Hello There!

It is Spring potential energy. Also called Elastic potential energy.

Hope This Helps You!
Good Luck :)

- Hannah ❤

5 0

3 years ago

A ball is tossed with a velocity of 10 m/s directed vertically upward from a window located 20 m above the ground. Determine the

marusya05 [52]

Answer:

Explanation:

Given

Initial velocity of ball $u=10\ m/s$

height of window $h=20\ m$

Using Equation of motion

$y=ut+\frac{1}{2}at^2$

where u=initial velocity

t=time

a=acceleration

As ball is already is at a height of 20 m so

$Y=ut+\frac{1}{2}at^2+20$

$Y=10\times t+0.5\times (-9.8)t^2+20$

$Y=-4.9t^2+10t+20$

(b)highest point is obtained at v=0

$v^2-u^2=2as$

where

v=final velocity

u=initial velocity

a=acceleration

s=displacement

$(0)-10^2=2\times (-9.8)\times s$

$s=\frac{100}{19.6}$

$s=5.102\ m$

Highest Point will be $s+20=25.102\ m$

(c)Time taken when the ball hit the ground i.e. at Y=0

$-4.9t^2+10t+20=0$

$t=3.28\ s$

impact velocity $v=\sqrt{2\times 9.8\times 25.102}$

$v=22.181\ m/s$

7 0

3 years ago

Point charges q1 and q2 are separated by a distance of 60 cm along a horizontal axis. The magnitude of q1 is 3 times the magnitu

Alex777 [14]

d = distance between the two point charges = 60 cm = 0.60 m

r = distance of the location of point "a" where the electric field is zero from charge $q_{1}$ between the two charges.

$q_{1}$ = magnitude of charge on one charge

$q_{2}$ = magnitude of charge on other charge

$q_{1}$ = 3 $q_{2}$

$E_{1}$ = Electric field by charge $q_{1}$ at point "a"

$E_{2}$ = Electric field by charge $q_{2}$ at point "a"

Electric field by charge $q_{1}$ at point "a" is given as

$E_{1}$ = k $q_{1}$ /r²

Electric field by charge $q_{2}$ at point "a" is given as

$E_{2}$ = k $q_{2}$ /(d-r)²

For the electric field to be zero at point "a"

$E_{2}$ = $E_{1}$

k $q_{2}$ /(d-r)² = k $q_{1}$ /r²

$q_{2}$ /(d-r)² = 3 $q_{2}$ /r²

1/(0.60 - r)² = 3 /r²

r = 0.38 m

r = 38 cm

8 0

3 years ago