The tension in the rope B is determined as 10.9 N.
<h3>
Vertical angle of cable B</h3>
tanθ = (6 - 4)/(5 - 0)
tan θ = (2)/(5)
tan θ = 0.4
θ = arc tan(0.4) = 21.8 ⁰
<h3>Angle between B and C</h3>
θ = 21.8 ⁰ + 21.8 ⁰ = 43.6⁰
Apply cosine rule to determine the tension in rope B;
A² = B² + C² - 2BC(cos A)
B = C
A² = B² + B² - (2B²)(cos A)
A² = 2B² - 2B²(cos 43.6)
A² = 0.55B²
B² = A²/0.55
B² = 65.3/0.55
B² = 118.73
B = √(118.73)
B = 10.9 N
Thus, the tension in the rope B is determined as 10.9 N.
Learn more about tension here: brainly.com/question/24994188
#SPJ1
Answer: "One object speeds up before it slows to a stop
"
(the top one)
Explanation:
Ok, first a little recall on how to read this type of graph.
If the points are far apart, the object is moving fast.
If the points are close together, the object is moving slow.
If the distance between the points changes then the velocity of the object changes, which means that the object is accelerated.
If we have a lot of points clustered in one location, then the object is not moving.
We can see:
The top object starts slow, then it increments the speed, then it slows down again, and then it comes to stop.
The bottom object starts fast, and it slows down.
then:
"One object speeds up before it slows to a stop
"
This describes the motion of the top object, this is the only correct option that describes one of the graphs.
Answer:
1125.66956 N
Explanation:
m = Mass of stunt performer
g = Acceleration due to gravity = 9.81 m/s²
v = Velocity of the swing = 7 m/s
T = Tension
r = Radius of the swing = Length of vine = 11.5 m
From the free body diagram
The minimum tension force the vine must be able to support without breaking is 1125.66956 N
If the vertical component is 29.6 m/s down, and the horizontal component
is 54.8 m/s parallel to the surface, then the magnitude of the slanty vector is
√(29.6² + 54.8²) = √(876.16 + 3003.04) = √3879.2 = 62.28 m/s .
That's 139 mph ! Wow !
I know one is transformed, not sure about another
