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2 years ago

5

A vehicle in for repair has a burst upper radiator tank. Technician A says thermostat that was stuck in the open position could

be the cause. Technician B says that a faulty radiator pressure cap could be the cause. Who is correct?

1 answer:

Morgarella [4.7K]2 years ago

5 0

Answer:

Technician B

Explanation:

A thermostat being stuck in an open position allows coolant to constantly circulate through the radiator which will cause a drop in the temperature of the engine. Hence, thermostat being stuck in an open position has nothing to do with burst upper radiator.

On the other hand, a radiator cap controls the pressure within the radiator which needs to be kept constant in order prevent overheating or damage to the radiator itself.

Therefore, technician B is correct.

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Help me, i don't know the answer

8_murik_8 [283]

Explanation:

1)

A) Bb BB

B) 50%

2)

A) 50%

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1 year ago

Two 0.20-kg balls, moving at 4 m/s east, strike a wall. Ball A bounces backwards at the same speed. Ball B stops. Which statemen

muminat

Answer:

Option A

Explanation:

From the question we are told that:

Mass $m=0.20kg$

Velocity $v=4m/s$

Generally the equation for momentum for Ball A is mathematically given by

Initial Momentum

$M_{a1}=mV$

$M_{a1}=0.2*4$

$M_{a1}=0.8$

Final Momentum

$M_{a2}=-0.8kgm/s$

Therefore

$\triangle M_a=-1.6kgm/s$

Generally the equation for momentum for Ball B is mathematically given by

Initial Momentum

$M_{b1}=mV$

$M_{b1}=0.2*4$

$M_{b1}=0.8$

Final Momentum

$M_{b2}=-0 kgm/s$

Therefore

$|\triangle M_a|>|\triangle Mb|$

Option A

4 0

2 years ago

Jane believes that plate tectonics is a theory, and Mario believes it is a law. Which of the following best supports Jane’s argu

Gekata [30.6K]

Answer:

its d

Explanation:

i did this and got it right

8 0

2 years ago

Read 2 more answers

A 51.0 kg crate, starting from rest, is pulled across a floor with a constant horizontal force of 225 N. For the first 10.0 m th

shepuryov [24]

Answer:

The final speed of the crate is 12.07 m/s.

Explanation:

For the first 10.0 meters, the only force acting on the crate is 225 N, so we can calculate the acceleration as follows:

$F = ma$

$a = \frac{F}{m} = \frac{225 N}{51.0 kg} = 4.41 m/s^{2}$

Now, we can calculate the final speed of the crate at the end of 10.0 m:

$v_{f}^{2} = v_{0}^{2} + 2ad_{1}$

$v_{f} = \sqrt{0 + 2*4.41 m/s^{2}*10.0 m} = 9.39 m/s$

For the next 10.5 meters we have frictional force:

$F - F_{\mu} = ma$

$F - \mu mg = ma$

So, the acceleration is:

$a = \frac{F - \mu mg}{m} = \frac{225 N - 0.17*51.0 kg*9.81 m/s^{2}}{51.0 kg} = 2.74 m/s^{2}$

The final speed of the crate at the end of 10.0 m will be the initial speed of the following 10.5 meters, so:

$v_{f}^{2} = v_{0}^{2} + 2ad_{2}$

$v_{f} = \sqrt{(9.39 m/s)^{2} + 2*2.74 m/s^{2}*10.5 m} = 12.07 m/s$

Therefore, the final speed of the crate after being pulled these 20.5 meters is 12.07 m/s.

I hope it helps you!

7 0

2 years ago

Describe the interactive roles and statuses of individuals and groups in your conmunity

marta [7]

Social groups<span> that we as </span>individuals<span> belong to, we have a </span>status<span> and a </span>role<span> to fulfill.</span>Status<span> is our relative social position within a </span>group<span>, while a </span>role<span> is ... Because of this </span>status<span>, he is expected to fulfill a </span>role<span> for his children ... These make it a crime to hire and promote people because they are </span>your<span> relatives.
put me as a brainiest </span><span />

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2 years ago