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3 years ago

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On a field trip, there are 8 adults and 24 students. What is the ratio of students to the total number of people on the field tr

ip?
A. 8 to 24
B. 1 to 4
C.32 to 24
D. 3 to 4
TIP: its not c

1 answer:

nasty-shy [4]3 years ago

8 0

What is the ratio of Students to the total number of people on the field trip?

Answer-
D) 3/4

We are looking for the ratio of students to total people. That would be 24/32. We need to simplify that. Simplified, that would be 3/4.

-Brainly Answerer

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Ryan $65 for n books. Write an expression that can be used to find the cost of one book.

eimsori [14]

Answer:

x=65/n where x is 1 book and n the number of books

Step-by-step explanation:

If n is the number of books, lets say 1 book is "x", then

nx=65

x=65/n

for example

n=1 then x=65

n=2 then x=65/2

n=3 then x=65/3

5 0

3 years ago

I know you want to answer this question.

Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

$\frac{1}{2} ^{x-4}$ - 3 = $4^{x-3}$ - 2

First, convert $4^{x-3}$ to base 2:

$4^{x-3}$ = $(2^{2})^{x-3}$

$\frac{1}{2} ^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Next, convert $\frac{1}{2} ^{x-4}$ to base 2:

$\frac{1}{2} ^{x-4}$ = $(2^{-1})^{x-4}$

$(2^{-1})^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{-1})^{x-4}$ = $2^{-1*(x-4)}$

$2^{-1*(x-4)}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{2})^{x-3}$ = $2^{2(x-3)}$

$2^{-1*(x-4)}$ - 3 = $2^{2(x-3)}$ - 2

Apply exponent rule: $a^{b+c}$ = $a^{b}$ $a^{c}$ :

$2^{-1(x-4)}$ = $2^{-1x}$ * $2^{4}$ , $2^{2(x-3)}$ = $2^{2x}$ * $2^{-6}$

$2^{-1 * x}$ * $2^{4}$ - 3 = $2^{2x}$ * $2^{-6}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$2^{-1x}$ = $(2^{x})^{-1}$ , $2^{2x}$ = $(2^{x})^{2}$

$(2^{x})^{-1}$ * $2^{4}$ - 3 = $(2^{x})^{2}$ * $2^{-6}$ - 2

Rewrite the equation with $2^{x} = u$ :

$(u)^{-1}$ * $2^{4}$ - 3 = $(u)^{2}$ * $2^{-6}$ - 2

Solve $u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2:

$u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2

Refine:

$\frac{16}{u}$ - 3 = $\frac{1}{64}$ $u^{2}$ - 2

Add 3 to both sides:

$\frac{16}{u}$ - 3 + 3 = $\frac{1}{64}$ $u^{2}$ - 2 + 3

Simplify:

$\frac{16}{u}$ = $\frac{1}{64}$ $u^{2}$ + 1

Multiply by the Least Common Multiplier (64u):

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify:

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify $\frac{16}{u}$ * 64u:

1024

Simplify $\frac{1}{64}$ $u^{2}$ * 64u:

$u^{3}$

Substitute:

1024 = $u^{3}$ + 64u

Solve for u:

u = 8

Substitute back u = $2^{x}$ :

8 = $2^{x}$

Solve for x:

x = 3

4 0

3 years ago

Round 36.319 to the nearest tenth

vampirchik [111]

36.3 because the digit in the hundredths place is not 5 or greater

3 0

3 years ago

Read 2 more answers

Point (6, 0) lies on the<br><br> X-axis<br> Oy-axis<br> line y = x

tresset_1 [31]

Answer:

x - axis

Step-by-step explanation:

Since, y-coordinate of point (6, 0) is zero.

Hence, it lies on x - axis.

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3 years ago

Read 2 more answers

-(6x+6)+2=-6x-3 please solve

makkiz [27]

Answer:

There is no solution.

Step-by-step explanation:

To solve, use the order of operations. Follow them until you solve for x or just numbers remain.

-(6x + 6) + 2 = -6x - 3

-6x - 6 + 2 = -6x - 3

-6x - 4 = -6x - 3

-4 = -3

The answer is no solution since this is a false statement.

3 0

3 years ago