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valentina_108 [34]
3 years ago
8

Sanji paid 25 for two scarves which were different prices when she got home she could not find the receipt she remember that one

scarf cost three dollars more than the other what was the price of the more expensive scarf
Mathematics
1 answer:
laila [671]3 years ago
5 0
Answer:

The answer is x = 14 the more expensive scarf

Step-by-step explanation:

x + y = 25

3 + y + y = 25 (x = 3 + y)

3 + 2y = 25

2y = 25 - 3

2y = 22

y = 22/2

y = 11

x = 3 + y

x = 3 + 11

x = 14 (the more expensive scarf)

(x,y) ; (14,11)
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Someone answer this please
navik [9.2K]

Answer:

b = 33m is the answer

Step-by-step explanation:

a = 44m

b = ?

c = 55m

According to the Pythagoras theorem,

a² + b² = c²

44² + b² = 55²

1936 + b² = 3025

b² = 3025 - 1936

b² = 1089

b = 33m

∴ b = 33m is the length of the missing leg.

3 0
2 years ago
The radius of a circle is 42 inches. What is the circle's area?<br> Use 3.14 for ​.
Mazyrski [523]

Answer:

A =5538.96 in^2

Step-by-step explanation:

The area of a circle is given by

A = pi r^2

We know the radius is 42 and pi is approximated by 3.14

A = 3.14 * 42^2

A =5538.96 in^2

3 0
2 years ago
Read 2 more answers
Mrs. Shelly paid $3 for 6 muffins and Mrs. Kloske paid $9 for 18 muffins. Is the amount Mrs. Kloske and Mrs. Shelly paid equival
Mrac [35]
Yes, because you can multiply $3 by 3 to get $9 and 6 muffins by 3 to get 9 muffins.
8 0
3 years ago
Read 2 more answers
22 to the 7 power minus 22 to the 4 power
nasty-shy [4]
22^7 - 22^4 = 2,494,123,632 .
7 0
3 years ago
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Write the standard form equation of the ellipse shown in the graph, and identify the foci.
vlada-n [284]

Answer option A

From the given graph is a Vertical ellipse

Center of ellipse = (-2,-3)

Vertices are (-2,3)  and (-2,-9)

Co vertices are (-6,-3) and (2,-3)

The distance between center and vertices = 6, so a= 6

The distance between center and covertices = 4 , so b= 4

The general equation of vertical ellipse is

\frac{(x-h)^2}{b^2} + \frac{(y-k)^2}{a^2}=1

(h,k) is the center

we know center is (-2,-3)

h= -2, k = -3 , a= 6  and b = 4

The standard equation  becomes

\frac{(x+2)^2}{4^2} + \frac{(y+3)^2}{6^2}=1

\frac{(x+2)^2}{16} + \frac{(y+3)^2}{36}=1

Foci  are (h,k+c)  and (h,k-c)

c=\sqrt{a^2-b^2}

Plug in the a=6  and b=4

c=\sqrt{6^2-4^2}

 c=\sqrt{20}

  c=2\sqrt{5}, we know h=-2  and k=-3

Foci  are   (-2,-3+2\sqrt{5})  and  (-2,-3-2\sqrt{5})

Option A is correct

6 0
3 years ago
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