1) √3 √7 = √21
2) √5 √245 = √5 √5 * 49 = √5 * 7√5 = 7 √5 * 5 = 7 √25 = 7 * 5 = 35
3) √77 ÷ √11 = as is. can't be simplified.
4) (√59)² = 59 ; the square root was cancelled by squared.
5) 3√6 x 8√7 = 3 * 8 √6 * 7 = 24 √42
6) 5√3 x 6 √3 = 5 * 6 √3 * 3 = 30 √9 = 30 * 3 = 90
7) 40√30 ÷ 5√3 = (40 / 5) * (√30 /√3) = 8 * ((√3 *10) / √3) = 8 √10
8) (6√5)² = 6² * √5² = 36 * 5 = 180
Answer:
2n-4
Step-by-step explanation:
You're subtracting 4 from the product of n times 2
Answer: 10 , 13 , 14 , 15
Step-by-step explanation:
To find the perimeter of a quadrilateral , we will add all its side , that is
Perimeter = x + x + 3 + x + 4 + x + 5
That is
52 = x + x + 3 + x + 4 + x + 5
52 = 4x + 12
subtract 12 from both sides
40 = 4x
divide through by 4
x = 10
therefore , the lengths of the sides are
10 , 10+3 , 10 + 4 , 10 + 5 , that is
10 , 13 , 14 , 15
<span><span>Step 1: Find a number you can multiply by the bottom of the fraction to make it 10, or 100, or 1000, or any 1 followed by 0s.
</span><span>Step 2: Multiply both top and bottom by that number.
</span><span>Step 3.Then write down just the top number, putting the decimal point in the correct spot (one space from the right hand side for every zero in the bottom number)</span></span><span>
Hope i helped :[)</span>
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