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Setler79 [48]
4 years ago
7

How is the graph of y = –x2 – 1 different from the graph of y = –x2?

Mathematics
1 answer:
KonstantinChe [14]4 years ago
5 0

Every transformation like

f(x)\mapsto f(x)+k

translated the graph vertically, k units up if k is positive, k units down if k is negative.

So, in your case, we have that -x^2-1 is the same graph as -x^2, except it's shifted 1 unit down.

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Step-by-step explanation:

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Answer:

Equivalent expressions

A) \frac{60}{-5}

C)  60\times (-\frac{1}{5})

Step-by-step explanation:

Given expression :

\frac{-60}{5}

Choices given :

A) \frac{60}{-5}

B) 60\times \frac{1}{5}

C)  60\times (-\frac{1}{5})

D) -60\times (-\frac{1}{5})

To find the equivalent expression.

We will first evaluate the given expression.

\frac{-60}{5}

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Evaluating each choice to select the equivalents.

A) \frac{60}{-5}

⇒ -12    [Quotient of a positive dividend and a negative divisor is always negative]

B) 60\times \frac{1}{5}

⇒ \frac{60}{5}

⇒ 12

C)  60\times (-\frac{1}{5})

⇒ -\frac{60}{5}   [Product of a positive and a negative is always a negative]

⇒ -12

D) -60\times (-\frac{1}{5})

⇒ \frac{60}{5}   [Product of two negatives is always a positive]

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∴ We see that the choices A and C are equivalent.

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