Answer:
25% increase
Step-by-step explanation:
Answer:
14/13
Step-by-step explanation:
19/13-5/13=14/13
Since the denominators are the same, you just do the subtraction of the nominators.
Answer: 10
<u>Step-by-step explanation:</u>
varies directly means: 
Step 1: solve for k ⇒ 
Step 2: plug in the given value and k to solve for the missing value: 
42(5) = 21(x)
2(5) = x
10 = x
Answer:
B, C, and E
Step-by-step explanation:
<u>Simplify all answer choices:</u>
A.
5(2x+10)+1=
10x+50+1=
10x+51
B.
7(x+2)+3x-3=
7x+14+3x-3=
10x+11
C.
3(3x+4)+x-1=
9x+12+x-1=
10x+11
D.
2(6x+4)+2x+5=
12x+8+2x+5=
14x+13
E.
2(6x+5)-2x+1=
12x+10-2x+1=
10x+11
Answer choices B, C, and E simplify to 10x+11
Answer:
a) P ( E | F ) = 0.54545
b) P ( E | F' ) = 0
Step-by-step explanation:
Given:
- 4 Coins are tossed
- Event E exactly 2 coins shows tail
- Event F at-least two coins show tail
Find:
- Find P ( E | F )
- Find P ( E | F prime )
Solution:
- The probability of head H and tail T = 0.5, and all events are independent
So,
P ( Exactly 2 T ) = ( TTHH ) + ( THHT ) + ( THTH ) + ( HTTH ) + ( HHTT) + ( HTHT) = 6*(1/2)^4 = 0.375
P ( At-least 2 T ) = P ( Exactly 2 T ) + P ( Exactly 3 T ) + P ( Exactly 4 T) = 0.375 + ( HTTT) + (THTT) + (TTHT) + (TTTH) + ( TTTT)
= 0.375 + 5*(1/2)^4 = 0.375 + 0.3125 = 0.6875
- The probabilities for each events are:
P ( E ) = 0.375
P ( F ) = 0.6875
- The Probability to get exactly two tails given that at-least 2 tails were achieved:
P ( E | F ) = P ( E & F ) / P ( F )
P ( E | F ) = 0.375 / 0.6875
P ( E | F ) = 0.54545
- The Probability to get exactly two tails given that less than 2 tails were achieved:
P ( E | F' ) = P ( E & F' ) / P ( F )
P ( E | F' ) = 0 / 0.6875
P ( E | F' ) = 0
