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2 years ago

What do I do? what's Ax??

Mathematics

1 answer:

Liono4ka [1.6K]2 years ago

5 0

$A=\left[\begin{array}{ccc}5&-4\\3&6\end{array}\right] \\\\A_x=\left[\begin{array}{ccc}12&-4\\66&6\end{array}\right]$

$|A_x|=\left|\begin{array}{ccc}12&-4\\66&6\end{array}\right|=(12)(6)-(66)(-4)=72+264=336$

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The statement tan theta -12/5, csc theta -13/5, and the terminal point determined by theta is in quadrant 2."

Harlamova29_29 [7]

Answer:

Answer C:

Cannot be true because $csc(\theta)$ is greater than zero in quadrant 2.

Step-by-step explanation:

When the csc of an angle is negative, since the cosecant function is defined as:

$csc(\theta)=\frac{1}{sin(\theta)}$

that means that the sin of the angle must be negative, and such cannot happen in the second quadrant. The sine function is positive in the first and second quadrant.

Therefore, the correct answer is:

Cannot be true because $csc(\theta)$ is greater than zero in quadrant 2.

6 0

3 years ago

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beks73 [17]

The result of expanding the trigonometry expression $\sin^2(\theta) * (1 + \cos(\theta))$ is $cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

<h3>How to evaluate the expression?</h3>

The expression is given as:

$\sin^2(\theta) * (1 + \cos(\theta))$

Express $\sin^2(\theta)$ as $1 - \cos^2(\theta)$ .

So, we have:

$\sin^2(\theta) * (1 + \cos(\theta)) = (1- \cos^2(\theta)) * (1 + \cos(\theta))$

Open the bracket

$\sin^2(\theta) * (1 + \cos(\theta)) = 1 + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Express 1 as cos°(Ф)

$\sin^2(\theta) * (1 + \cos(\theta)) = cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Hence, the result of expanding the trigonometry expression $\sin^2(\theta) * (1 + \cos(\theta))$ is $cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Read more about trigonometry expressions at:

brainly.com/question/8120556

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3 0

2 years ago

The solution set for 7q^2-28=0

kherson [118]

7q² - 28 = 0
   + 28 + 28
   7q² = 28
       7 7
   q² = 4
      q = ±4
      q = 4 or q = -4

Solution Set: {±4} and {q|q = 4 or q = -4}

8 0

2 years ago

What is the value of the expression when p = –24 and q = 4?<br><br><br><br><br> p/2q

Tomtit [17]