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3 years ago

What do I do? what's Ax??

Mathematics

1 answer:

Liono4ka [1.6K]3 years ago

5 0

$A=\left[\begin{array}{ccc}5&-4\\3&6\end{array}\right] \\\\A_x=\left[\begin{array}{ccc}12&-4\\66&6\end{array}\right]$

$|A_x|=\left|\begin{array}{ccc}12&-4\\66&6\end{array}\right|=(12)(6)-(66)(-4)=72+264=336$

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3 1/2 - 1 1/3 x x= 1

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Answer:

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Step-by-step explanation:

Given as :

The expression is written

3 $\dfrac{1}{2}$ - 1 $\dfrac{1}{3}$ × x = 1

Or, 1 $\dfrac{1}{3}$ × x = 3 $\dfrac{1}{2}$ - 1

Or, $\frac{(1\times 3) + 1}{3}$ × x = $\frac{(3\times 2) + 1}{2}$ - 1

Or, $\dfrac{4}{3}$ × x = $\dfrac{7}{2}$ - 1

Or, $\dfrac{4}{3}$ × x = $\dfrac{7-2}{2}$

Or, $\dfrac{4}{3}$ × x = $\dfrac{5}{2}$

∴ x = $\frac{\frac{5}{2}}{\frac{4}{3}}$

Or, x = $\frac{5\times 3}{2\times 4}$

I.e x = $\frac{15}{8}$

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Answer:

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Step-by-step explanation:

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