Two years ago a man was six times as old as his daughter. In 18 years he will be twice as old as his daughter. Determine their p
resent ages.
2 answers:
Answer:
7 and 32
Step-by-step explanation:
Answer:
Step-by-step explanation:
f- 2 = 6(d-2)
f - 2 = 6d - 12
f = 6d - 12 + 2
f = 6d - 10 .................................... eq 1
f + 18 = 2(d+18)
f + 18 = 2d + 36
f= 2d + 36 - 18
f = d + 18 .......................................... eq 2
eq1=eq2
6d - 10 = 2d + 18
6d - 2d = 18 + 10
4d = 28
d = 28/4
d = 7 yrs is the daughter's age
Take eq 1
f = 6(7) - 10
f = 42 - 10
f = 32 yrs is Father's age
You might be interested in
Answer:
The answer is three please give brainliest:D
Step-by-step explanation:
Answer:
In the pic
Step-by-step explanation:
If you have any questions about the way I solved it, don't hesitate to ask me in the comments below ÷)
Answer:
2.56 * 10^11 L
Step-by-step explanation:
1 body has 40 L
Thus, the amount in 6.4 billion would be;
40 * 6.4 * 10^9
= 256 * 10^9
= 2.56 * 10^2 * 10^9
= 2.56 * 10^11 L
The answer is £64.89.
Step by Step:
Take the original price multiplied by 0.03 ( the percent of a booking fee ) and add those amounts together.
Equation: 63 + 1.89 = 64.89
Answer:
i dont see it
Step-by-step explanation:
