What is the answer to this

You are standing at rest at a bus stop. A bus moving at a constant speed of 5.00 mm/???????? passes you. When the rear of the bu

neonofarm [45]

Answer:

You run 74.1409 mm and you are running at 11.9311 mm/s

Explanation:

If the bus is moving at a constant speed of 5.00mm/s and you start to run when the bus pass you by 12 mm, the equation that describe the position of the bus is:

Xb = 12.0 mm + (5.00 mm/s)*t

Where t is the time in seconds.

If you start to run toward it with a constant acceleration of 0.960 mm/s2, the equation that describe your position is:

$X_y=\frac{1}{2} (0.960\frac{mm}{s^{2}})*t^{2}$

So, the time t when you catch up the rear of the bus is the time when Xb is equal to Xy. This is:

$X_b=X_y\\12+5t=\frac{1}{2} 0.960t^{2} \\0.48t^{2}-5t-12=0$

Then, solving the quadratic equation, we obtain that t is equal to 12.4282 s

So, if we replace this value of t in the equation of Xy, we obtain how far you have run before you catch up with the rear of the bus. This is:

$X_y=\frac{1}{2} (0.960\frac{mm}{s^{2}})*12.4282^{2}$

Xy = 74.1409 mm

Then, the equation of your velocity a time t can be write as:

$Vy=0.960\frac{mm}{s^{2} }*t$

So, the velocity when you catch up the rear of the bus is:

$Vy=0.960\frac{mm}{s^{2} }*12.4282s$

Vy = 11.9311 mm/s

3 0

3 years ago

Read 2 more answers

Magnetic field strength decreases as you get farther from the poles of the magnet. does the flux through the face of the coil ch

brilliants [131]

Magnetic field strength decreases as you get farther from the poles of the magnet.

<h3>Explanation</h3>

There are three ways to change the magnetic flux across a loop: Change the strength of the magnetic field across the surface (raise, reduce).

It doesn’t matter whether you move the coil while keeping the magnet fixed or the other way around if you want to change the surface area of the loop (raise by expanding the loop, decrease by reducing the loop).

The way they move in respect to one another determines how the magnetic flux across the coil changes. The direction in which the galvanometer needle deflects depends on which side of the coil confronts the magnet when you move it. The coil ends are labelled to show which goes to the red wire and which goes to the black wire.

To know more about magnetic flux visit:

brainly.com/question/16960581

#SPJ4

5 0

2 years ago

Say you want to make a sling by swinging a mass M of 1.7 kg in a horizontal circle of radius 0.048 m, using a string of length 0

DENIUS [597]

Answer:

Tension in the string is equal to 58.33 N ( this will be the strength of the string )

Explanation:

We have given mass m = 1.7 kg

radius of the circle r = 0.48 m $F=\frac{mv^2}{r}=\frac{1.7\times 4.05^2}{0.48}=58.33N$

Kinetic energy is given 14 J

Kinetic energy is equal to $KE=\frac{1}{2}mv^2$

So $\frac{1}{2}\times 1.7\times v^2=14$

$v^2=16.47$

v = 4.05 m/sec

Centripetal force is equal to $F=\frac{mv^2}{r}=\frac{1.7\times 4.05^2}{0.48}=58.33N$

So tension in the string will be equal to 58.33 N ( this will be the strength of the string )

3 0

3 years ago

1. The variable ______________ describes how quickly something moves. a) time c) speed b)position d) mass

dem82 [27]

Speed is the answer because it is the rate that something or someone is able to move.

5 0

4 years ago

What is a refracted wave? Give an example.

olchik [2.2K]

A refracted wave is a wave whose path has been bent

as a result of traveling out of one medium and into into

a different medium, or through a medium whose properties

change slightly and gradually over a substantial distance.

Example #1:

The light waves that enter your eyes as you look down from a

bridge and watch a fish in the creek below you. The fish is not

where you think it is. The light waves coming from it are refracted

when they travel out of the water and into the air. Your brain doesn't

include that bend in its calculations, and it naturally assumes that the

fish is in the direction the light waves are coming from. But it's actually

in a slightly different direction.

Example #2.

If you wear glasses or contacts, then all the light waves you see

through them are refracted on their way through your 'corrective

lenses' before they enter your eyes.

Example #3.

When you listen to an AM radio station at night that's located in

a city very far away from you, the radio waves you're receiving

are coming at you from a direction in the sky.

Now you KNOW that the radio station is not located there. Some of

the radio waves from the station leave the transmitting tower at an angle high above the ground, and head off into the sky. As they travel far through the air ... sometimes hundreds or even thousands of miles ... the properties of the air change gradually, and the radio waves are gradually refracted as they travel, eventually curving downward toward the ground again.

(I'm writing this answer while I'm on a buisness trip to a city that's

about 650 miles from home. Two nights ago, while I was in the car,

I got a little bit curious, and I tuned the car radio to a popular AM radio

station back in my home town, just to see.

And there it was ! Booming in. 5 by 9 with practically no Q R Mary.)

8 0

3 years ago