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Fittoniya [83]
3 years ago
11

What is the median for the data set?

Mathematics
1 answer:
DiKsa [7]3 years ago
5 0
1st step is to put the numbers from smallest to biggest. Once you do that cross one out on the left, then the right, then the left, then the right and so on. Sometimes there will be 2 numbers left, so you add them up and subtract by two. If you need further help ask! :)
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Which of the following is the maximum value of the equation y = −x2 − x + 6?
Ratling [72]

Step-by-step explanation:

f(x) = y= -x²-x+6

When y is max, f'(x) = 0

f'(x) = -2x-1

Equating to 0,

-2x-1= 0

x= -1/2

Put the value of x in f(x)

y = -(-1/2)² -(-1/2) +6

= -1/4+1/2+6

= 6+1/2

y= 13/2

4 0
2 years ago
Ms. Lynette earns $19.50 an hour when she works overtime. She worked overtime twice this week. One day she worked 3 hours of ove
algol13
(19.50*3)+(19.50*x)=146.25
8 0
3 years ago
Read 2 more answers
Select the correct way to write 0.28 as a fraction.
Basile [38]
7/25 is equal to 0.28
5 0
3 years ago
Emily jogged 8 miles due north, then turned east and jogged 15 miles. How many miles is
elena55 [62]

Answer:

The answer is 120

Step-by-step explanation:

I got it by timing 8 and 15 , and I got 120

8 0
3 years ago
Answer for all please
malfutka [58]

Answer:

a) 'X' be the random variable in discrete distribution

b) <em> The value of y = 0.2</em>

<em>c) The mean value or  Expectation value</em>

<em>E (X) = 1.25</em>

<em>d) </em>

<em>The variance σ² of the discrete distribution function is</em>

<em>Variance ( V(x)= 1.2875</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given data

 x    :      0              1        2        3        4

P(x)  :     0.30      0.35      y      0.10   0.05

a)

  Let 'X' be the random variable in discrete distribution

 Given data is discrete distribution

<em>i) If the numbers </em>p(x_{i} )\geq 0  for all values of 'i'

ii) ∑P(x) = 1

Given data <em> </em>p(x_{i} )\geq 0  for all values of 'i'

∑P(x) = 1

0.30+0.35+y+0.10+0.05 =1

                  y + 0.8 = 1

                 y = 1 -0.8 = 0.2

<em>b) The value of y = 0.2</em>

<u><em>Step(ii):-</em></u>

<u><em>Expectation:</em></u>

Given data

 x    :      0              1          2        3        4

P(x)  :     0.30      0.35      0.2      0.10   0.05

<em>The mean value or  Expectation value</em>

<em>E (x) = ∑ x p ( X = x)</em>

<em>         =  0 × 0.30 + 1 × 0.35 + 2 × 0.2 + 3 × 0.10 + 4 × 0.05</em>

<em>        =     0 + 0.35 + 0.4 + 0.30 + 0.2</em>

<em>       =       1.25</em>

<u><em>Variance of X</em></u>

The variance σ² of the discrete distribution function is defined by

                σ²  = ∑ x² p(x=x) - μ²

                     = 0× 0.30 + 1² × 0.35 + 2²× 0.2 +3²× 0.10 + 4²× 0.05 - (1.25)²

                    = 0 + 0.35 + 0.8 + 0.9 + 0.8 - 1.5625

                   = 1.2875

<u><em>conclusion:-</em></u>

<em>The mean value or  Expectation value = 1.25</em>

<em>The variance σ² of the discrete distribution function</em>

<em>  V(X) = 1.2875</em>

   

3 0
3 years ago
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