The deck on a home is shaped like a parallelogram. The parallelogram has an area of 544.5 ft2 and a base measurement of 16.5 ft.
2 answers:
<u><em>Answer:</em></u>
The height of the parallelogram is 33 ft
<u><em>Explanation:</em></u>
<u>The area of the parallelogram can be calculated using the following rule:</u>
Area of parallelogram = base * height
<u>In the problem, we are given that:</u>
Area = 544.5 ft²
Base = 16.5 ft
<u>Substitute with the given values in the above equation and solve for the height as follows:</u>
Area = base * height
544.5 = 16.5 * height
Hope this helps :)
You might be interested in
The given function has no undefined points nor domain constraint. Thus, the domain is: .
<h3>Domain and Range</h3>
The domain of a function is the set of input values for which the function is real and defined. In the other words, when you define the domain, you are indicating for which values x the function is real and defined. An example, there is a restriction for the domain of fractions. The variable x in the denominator should be different of zero.
While the domain is related to the values of x, the range is related to the possible values of y that the function can have.
In this question, the function has no undefined points nor domain constraint. Therefore, the domain is:
Learn more about the domain here:
#SPJ1
1. Consider the function 
.
It is a linear function, so to draw its graph 2 points are enough:
f(4)=(3/4)*4-2=3-2=1
f(0)=(3-4)*0-2=-2
so 2 points on this line are (0, -2) and (4, 1). Check the picture 1:
2. The problem considers the inequality y>f(x)
a. the slope of the line y=ax+b is the coefficient of x, so a. In our case a=3/4, not -2
b. The graph of any linear inequality is a shaded region, not a line or a shaded line.
c. Either the part below the line, or the part above the line will be shaded since we are talking about an inequality.
Check (4, -3), picture 2, which is clearly below the line.
now here y=-3, and f(4)=(3/4)(4)-2=3-2=1, so in this region y<f(x)=(3/4)x-2
So clearly the region where the inequality holds, so the region to color, is the part above the line.
d. The line itself is not dashed, only if we have an "equal to or smaller than" or "equal to or larger than" inequality.
e. (0, 0) is in the region above the line so YES, it is a solution.
We can also check it like this: y=0, f(0)=(3/4)0-2=-2 so y>f(0)
f. The y-intercept is always f(0). In this case f(0)=-2
It is a linear function, so to draw its graph 2 points are enough:
f(4)=(3/4)*4-2=3-2=1
f(0)=(3-4)*0-2=-2
so 2 points on this line are (0, -2) and (4, 1). Check the picture 1:
2. The problem considers the inequality y>f(x)
a. the slope of the line y=ax+b is the coefficient of x, so a. In our case a=3/4, not -2
b. The graph of any linear inequality is a shaded region, not a line or a shaded line.
c. Either the part below the line, or the part above the line will be shaded since we are talking about an inequality.
Check (4, -3), picture 2, which is clearly below the line.
now here y=-3, and f(4)=(3/4)(4)-2=3-2=1, so in this region y<f(x)=(3/4)x-2
So clearly the region where the inequality holds, so the region to color, is the part above the line.
d. The line itself is not dashed, only if we have an "equal to or smaller than" or "equal to or larger than" inequality.
e. (0, 0) is in the region above the line so YES, it is a solution.
We can also check it like this: y=0, f(0)=(3/4)0-2=-2 so y>f(0)
f. The y-intercept is always f(0). In this case f(0)=-2