Answer:
Rate law: = ![k[CS_2]^1](https://tex.z-dn.net/?f=k%5BCS_2%5D%5E1)
Explanation:
Given:
t ![[CS_2]](https://tex.z-dn.net/?f=%5BCS_2%5D)
0.100 
0.080 
0.055 
0.044 
Rate law for the given reaction: ![k[CS_2]^n](https://tex.z-dn.net/?f=k%5BCS_2%5D%5En)
Where, n is the order of the reaction.
Divide rate 1 with rate 3
![\frac{0.100}{0.055} =\frac{k[CS_2 (1)]^n}{k[CS_2 (3)]^n} \\\frac{0.100}{0.055} =\frac{k[2.7 \times 10^{-7}]^n}{k[1.5\times 10^{-7}]^n}\\1.81=[1.8]^n\\ n=1](https://tex.z-dn.net/?f=%5Cfrac%7B0.100%7D%7B0.055%7D%20%3D%5Cfrac%7Bk%5BCS_2%20%281%29%5D%5En%7D%7Bk%5BCS_2%20%283%29%5D%5En%7D%20%5C%5C%5Cfrac%7B0.100%7D%7B0.055%7D%20%3D%5Cfrac%7Bk%5B2.7%20%5Ctimes%2010%5E%7B-7%7D%5D%5En%7D%7Bk%5B1.5%5Ctimes%2010%5E%7B-7%7D%5D%5En%7D%5C%5C1.81%3D%5B1.8%5D%5En%5C%5C%20n%3D1)
So, rate law =
<span>Hydrogen ion, strictly, the nucleus of a hydrogen atom separated from its accompanying electron. The hydrogen nucleus is made up of a particle carrying a unit positive electric charge, called a proton.</span>
R = 1.3 A° = 1.3 × 10^(-10) m
V = 9.20277208×10^(−30) m.
Answer:
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Explanation:
Calculate the H positive from the pH equation: pH equals -log (H positive). This would be 10 to the -6.49. Let's call the acid HA. To calculate Ka in this equation, Ka equals H positive times A- over HA. HA is going to be the 0 0121. So, Ka=(10^-6.49)^2/0.0121. This equals 1.05*10^-13/0.0121. Ka then equals 8.65*10^-12.
