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AlekseyPX
3 years ago
11

1) A certain liquid has a density of 0.80 g/ml. What is the mass of a 40 ml sample of this liquid? 1)

Chemistry
1 answer:
Llana [10]3 years ago
8 0

Answer:

The answer is

<h2>32 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume = 40 mL

density = 0.80 g/mL

The mass is

mass = 40 × 0.8

We have the final answer as

<h3>32 g</h3>

Hope this helps you

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3 years ago
In the laboratory a student uses a "coffee cup" calorimeter to determine the specific heat of a metal. She heats 19.6 grams of z
storchak [24]

Answer:

The specific heat of zinc is 0.375 J/g°C

Explanation:

<u>Step 1: </u>Data given

Mass of zinc = 19.6 grams

Mass of water = 82.9 grams

Initial temperature of zinc T1= 98.37 °C

Initial temperature of water T1= 24.16 °C

Final temperature of water (and zinc) T2 = 25.70 °C

Specific heat of water = 4.184 J/g°C

<u>Step 2: </u>Calculate Specific heat of zinc

Q=m*c*ΔT

Qzinc = -Qwater

m(zinc)*C(zinc)*ΔT(zinc) = -m(water)*C(water)*ΔT(water)

⇒ with mass of water = 82.9 grams

⇒ with C(water) = 4.184 J/g°C

⇒ with ΔT(water) = T2 - T1 = 25.70 - 24.16 = 1.54

⇒ with mass of zinc = 19.6 grams

⇒ with C(zinc) = TO BE DETERMINED

⇒ with ΔT(zinc) = T2 -T1 = 25.70 - 98.37 = -72.67°C

Qzinc = -Qwater

m(zinc)*c(zinc)* ΔT(zinc) = - m(water)*c(water)* ΔT(water)

19.6g* C(zinc) * (-72.67°C) = - 82.9g* 4.184 J/g°C * 1.54 °C

-1424.332*C(zinc) = -534.155

C(zinc) = 0.375 J/g°C

The specific heat of zinc is 0.375 J/g°C

4 0
2 years ago
Why are some metals such as copper and aluminium not magnetic​
ioda

Answer:i dont know

Explanation:

I D

K

8 0
2 years ago
Hello people ~<br>Help me with this question.<br>Thanks in advance!​
Alekssandra [29.7K]

Hello!

The pollution due to oxides of sulfur gets enhanced due to the

presence of :

  • (a) particulate matter
  • (b) ozone
  • (d) hydrogen peroxide

∴ The correct option is : <u>(4) (a),(b),(d) only</u>

3 0
2 years ago
Determine the formula of chromic acid.
Katyanochek1 [597]

<u>Answer:</u> The formula of chromic acid is H_2CrO_4

<u>Explanation:</u>

We are given an ionic compound named as chromic acid. This acid is formed by the combination of hydrogen ion and chromate ion.

An acid is defined as the substance which releases hydrogen ion when dissolved in water.

Hydrogen is the 1st element of periodic table having electronic configuration of 1s^1.

This element will loose 1 electron to form H^{+} ion.

Chromate ion is a polyatomic ion having chemical formula of CrO_4^{2-}

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for the given compound is H_2CrO_4

Thus, the formula of chromic acid is H_2CrO_4

8 0
3 years ago
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