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Aliun [14]
3 years ago
8

How many grams of aluminum in required to produce 17.5 g of hydrogen

Chemistry
1 answer:
azamat3 years ago
6 0

Mass of Aluminum = 157.5 g

<h3>Further explanation</h3>

Given

17.5 g of Hydrogen

Required

Mass of Aluminum

Solution

Reaction

2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂

mol Hydrogen :

= mass : molar mass

= 17.5 g : 2 g/mol

= 8.75

From the equation, mol Al :

= 2/3 x mol H₂

= 2/3 x 8.75

= 5.83

Mass Al :

= 5.83 x 27 g/mol

= 157.5 g

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Answer:

Fire

Explanation:

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6 0
3 years ago
At a certain concentration of H2 and I2, the initial rate of reaction is 4.0 x 104 M / s. What would the initial rate of the rea
andreev551 [17]

The question is incomplete, here is the complete question:

The rate of certain reaction is given by the following rate law:

rate=k[H_2]^2[I_2]^2

At a certain concentration of H_2 and I_2, the initial rate of reaction is 4.0 × 10⁴ M/s. What would the initial rate of the reaction be if the concentration of

Answer : The initial rate of the reaction will be, 1.0\times 10^4M/s  

Explanation :

Rate law expression for the reaction:

rate=k[H_2]^2[I_2]^2

As we are given that:

Initial rate = 4.0 × 10⁴ M/s

Expression for rate law for first observation:

4.0\times 10^4=k[H_2]^2[I_2]^2 ....(1)

Expression for rate law for second observation:

R=k(\frac{[H_2]}{2})^2[I_2]^2 ....(2)

Dividing 2 by 1, we get:

\frac{R}{4.0\times 10^4}=\frac{k(\frac{[H_2]}{2})^2[I_2]^2}{k[H_2]^2[I_2]^2}

\frac{R}{4.0\times 10^4}=\frac{1}{4}

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Therefore, the initial rate of the reaction will be, 1.0\times 10^4M/s

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3 years ago
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<u>Explanation:</u>

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A sample of titanium dioxide having 59.95 % of titanium and another sample of titanium dioxide having 60.10 % of titanium.

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