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jeka57 [31]
3 years ago
6

Enough of a monoprotic acid is dissolved in water to produce a 0.0121 M solution. The pH of the resulting solution is 6.49. Calc

ulate the Ka for the acid.,
Chemistry
1 answer:
Hitman42 [59]3 years ago
4 0
Calculate the H positive from the pH equation: pH equals -log (H positive). This would be 10 to the -6.49. Let's call the acid HA. To calculate Ka in this equation, Ka equals H positive times A- over HA. HA is going to be the 0 0121. So, Ka=(10^-6.49)^2/0.0121. This equals 1.05*10^-13/0.0121. Ka then equals 8.65*10^-12.
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Answer: 2NOBr(g) ⇌ 2NO(g) + Br2(g)

Explanation: For volume changes in equillibrium, the following are to be taken into consideration:

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2NOBr(g) ⇌ 2NO(g) + Br2(g) is the equillibrium system because there are more moles of products,therefore an increase in the volume of the reaction will shift to the right and produce more moles of products. Also both reactants and products exist in the gaseous state and does not have equal number of moles.

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A salt bridge is used to provide electrons a path to flow from the electrode of one half-cell to another. TRUE FALSE
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