Divide 6000 by 20
= 300 programs for each perfomance
Answer:
3km
Step-by-step explanation:
When solving by substation the answer would be: X= 1 , y= 5
Answer:
![h = 162.0\ cm](https://tex.z-dn.net/?f=h%20%3D%20162.0%5C%20cm)
Step-by-step explanation:
Given
![BSA = \frac{\sqrt{w*h}}{60}](https://tex.z-dn.net/?f=BSA%20%3D%20%5Cfrac%7B%5Csqrt%7Bw%2Ah%7D%7D%7B60%7D)
Required
Find h, when BSA = 1.5 and w = 50
We have:
![BSA = \frac{\sqrt{w*h}}{60}](https://tex.z-dn.net/?f=BSA%20%3D%20%5Cfrac%7B%5Csqrt%7Bw%2Ah%7D%7D%7B60%7D)
Substitute 1.5 for BSA and 50 for w
![1.5 = \frac{\sqrt{50*h}}{60}](https://tex.z-dn.net/?f=1.5%20%3D%20%5Cfrac%7B%5Csqrt%7B50%2Ah%7D%7D%7B60%7D)
Multiply both sides by 60
![60*1.5 = \frac{\sqrt{50*h}}{60}*60](https://tex.z-dn.net/?f=60%2A1.5%20%3D%20%5Cfrac%7B%5Csqrt%7B50%2Ah%7D%7D%7B60%7D%2A60)
![60*1.5 = \sqrt{50*h](https://tex.z-dn.net/?f=60%2A1.5%20%3D%20%5Csqrt%7B50%2Ah)
![90 = \sqrt{50*h](https://tex.z-dn.net/?f=90%20%3D%20%5Csqrt%7B50%2Ah)
Square both sides
![90^2 = (\sqrt{50*h})^2](https://tex.z-dn.net/?f=90%5E2%20%3D%20%28%5Csqrt%7B50%2Ah%7D%29%5E2)
![90^2 = 50*h](https://tex.z-dn.net/?f=90%5E2%20%3D%2050%2Ah)
![90^2 = 50h](https://tex.z-dn.net/?f=90%5E2%20%3D%2050h)
![8100 = 50h](https://tex.z-dn.net/?f=8100%20%3D%2050h)
Divide both sides by 50
![\frac{8100}{50} = \frac{50h}{50}](https://tex.z-dn.net/?f=%5Cfrac%7B8100%7D%7B50%7D%20%3D%20%5Cfrac%7B50h%7D%7B50%7D)
![\frac{8100}{50} = h](https://tex.z-dn.net/?f=%5Cfrac%7B8100%7D%7B50%7D%20%3D%20h)
![162 = h](https://tex.z-dn.net/?f=162%20%3D%20h)
![h = 162](https://tex.z-dn.net/?f=h%20%3D%20162)
![h = 162.0\ cm](https://tex.z-dn.net/?f=h%20%3D%20162.0%5C%20cm)
<em>Hence, the patient's height is 162.0cm</em>
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Hello!
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❖ The distance is 9 units.
Add:
-7 + -2 = -9
You need a positive number so -9 becomes 9.
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