Answer:
TC (A) = 40x , TC (B) = 500 + 20x
Step-by-step explanation:
Let the number of students be = x
Hall A Total Cost
Relationship Equation, where TC (A) = f (students) = f (x) 40 per person (student) = 40x
Hall B Total Cost
Relationship Equation, where TC (B) = f (students) = f (x) 500 fix fee & 20 per person (student) = 500 + 20x
Answer:
15 pieces
Step-by-step explanation:
5/ (1/3) = 5*3 = 15
Answer:
125 defective jeans
Step-by-step explanation:
We are told that;
During inspections, 5 defective pairs of jeans are found in a shipment of 200 pairs of jeans .
We are supposed to determine the number of defective jeans in a shipment of 5000 pairs, if the trend continues.
Therefore;
5 defective = 200 pairs
What about in 5000 pairs?
Number of defective pairs = (5000 × 5 ) ÷ 200
= 125 defective pairs
Thus, in a shipment of 5000 pairs of jeans there will be 125 defective pairs
-Answer:Option B: Increase the amount of money they save each month by $80 from what they've been saving.
Step-by-step explanation: Only option B will allow them to meet their goal.
