All categories

4 years ago

5 1/4 takeaway 1 1/3 (please write answer as a mixed number)

2 answers:

5 0

The problems are quite easy to solve once you know the trick! I prefer to make mine improper fractions first, and then after solving turn it back into a mixed number. When you turn it into an improper fraction, you will have 21/4+4/3. Then, you can find the least common factor, which is 12, and multiply the numerator and denominator to make the denominator 12. Afterwards, you simply add the numerators, giving you 79/12. Finally, we must turn this back into a mixed number, so our final answer is 6 7/12.

sertanlavr [38]4 years ago

3 0

5 1/4 - 1 1/3 =
21/4 - 4/3 =
63/12 - 16/12 =
47/12 =
3 11/12 <==

You might be interested in

a) How many three-digit numbers can be formed from the digits 0, 1, 2, 3, 4, 5, and 6?6x7x7=294 b) How many three-digit numbers

love history [14]

Answer:

a) 294

b) 180

c) 75

d) 168

e) 105

Step-by-step explanation:

Given the numbers 0, 1, 2, 3, 4, 5 and 6.

Part A)

How many 3 digit numbers can be formed ?

Solution:

Here we have 3 spaces for the digits.

Unit's place, ten's place and hundred's place.

For unit's place, any of the numbers can be used i.e. 7 options.

For ten's place, any of the numbers can be used i.e. 7 options.

For hundred's place, 0 can not be used (because if 0 is used here, the number will become 2 digit) i.e. 6 options.

Total number of ways = $7 \times 7 \times 6$ = 294

Part B:

How many 3 digit numbers can be formed if repetition not allowed?

Solution:

Here we have 3 spaces for the digits.

Unit's place, ten's place and hundred's place.

For hundred's place, 0 can not be used (because if 0 is used here, the number will become 2 digit) i.e. 6 options.

Now, one digit used, So For unit's place, any of the numbers can be used i.e. 6 options.

Now, 2 digits used, so For ten's place, any of the numbers can be used i.e. 5 options.

Total number of ways = $6 \times 6 \times 5$ = 180

Part C)

How many odd numbers if each digit used only once ?

Solution:

For a number to be odd, the last digit must be odd i.e. unit's place can have only one of the digits from 1, 3 and 5.

Number of options for unit's place = 3

Now, one digit used and 0 can not be at hundred's place So For hundred's place, any of the numbers can be used i.e. 5 options.

Now, 2 digits used, so For ten's place, any of the numbers can be used i.e. 5 options.

Total number of ways = $3 \times 5 \times 5$ = 75

Part d)

How many numbers greater than 330 ?

Case 1: 4, 5 or 6 at hundred's place

Number of options for hundred's place = 3

Number of options for ten's place = 7

Number of options for unit's place = 7

Total number of ways = $3 \times 7 \times 7$ = 147

Case 2: 3 at hundred's place

Number of options for hundred's place = 1

Number of options for ten's place = 3 (4, 5, 6)

Number of options for unit's place = 7

Total number of ways = $1 \times 3 \times 7$ = 21

Total number of required ways = 147 + 21 = 168

Part e)

Case 1: 4, 5 or 6 at hundred's place

Number of options for hundred's place = 3

Number of options for ten's place = 6

Number of options for unit's place = 5

Total number of ways = $3 \times 6 \times 5$ = 90

Case 2: 3 at hundred's place

Number of options for hundred's place = 1

Number of options for ten's place = 3 (4, 5, 6)

Number of options for unit's place = 5

Total number of ways = $1 \times 3 \times 5$ = 15

Total number of required ways = 90 + 15 = 105

7 0

4 years ago

I need help with #6 please.

oksano4ka [1.4K]

Answer: $440

Steps:

Retrace the math. Your total at the end was $22.00, before that you had a 10% tax so you multiply the tax in order to retrace that step. Next, multiply is by 2 as the 50% discount which gets you to $440

5 0

4 years ago

A bag contains 8 blue marbles, 15 red marbles, 10 yellow marbles, and 3 brown marbles. If a marble is randomly selected, what is

nordsb [41]

8 add 15 add 10 add 3
36
So 3/36

8 0

3 years ago

Read 2 more answers

You guys can put A. B. C. D. or E.

AleksAgata [21]

Answer:

b and c

Step-by-step explanation:

4 0

3 years ago

While on vacation in Mexico Jeremiah reads a distance marker that indicates he is 89 kilometers from Juárez.If 1mile is approxim

Monica [59]

Answer:

55.27 miles

Step-by-step explanation:

Hello, I think I can help you with this

you can easily solve this by using a simple rule of three

Step one

If 1 mile is approximately 1.61 kilometers,it is

1 miles ⇔ 1.61 Kilometers

the, how many miles(x) are 89 km?

x ⇔ 89 kilometers

the relation is

$\frac{1\ mile}{1.61\ km}=\frac{x}{89\ km} \\$

Step two

solve for x( isolating x)

$\frac{1\ mile}{1.61\ km}=\frac{x}{89\ km} \\\frac{1\ mile*89\ km}{1.61\ km}=x\\x=55.27\ miles$

55.27 miles

Have a good day

5 0

3 years ago