No instructions? I'll assume you want the unit rate.

4 miles in 36 minutes = 4/36 miles in 1 minute, or 1/9 mile in 1 minute.

1 3/4 mile in 20 minutes? Multiply both figures by 3:

7 miles in 60 minutes, or 7 miles in 1 hour, or 7 mph.

8 0

3 years ago

Can someone explain inequality using a word problem

aleksandrvk [35]

What is the inequality between these two fractions 1/2 2/4: answer =...so you would write it out like this 1/2=2/4

8 0

3 years ago

Which expressions are completely factored? Select each correct answer. 18y^3−6y=3y(6y^2−2) 32y^10−24=8(4y^10−3) 20y^7+10y^2=5y(4

Vladimir79 [104]

Answer:

The expressions that completely factored are:

$32y^{10}-24$ = 8( $y^{10}-3$ ) ⇒ 2nd

$16y^{5}+12y^{3}=4y^{3}(4y^{2}+3)$ ⇒ 4th

Step-by-step explanation:

Complete factorization means the terms in the bracket has no common factor

∵ The expression is 18y³ - 6y

- Find the greatest common factor of the numbers and the variable

∵ The greatest common factor of 18 and 6 is 6

∵ The greatest common factor of y³ and y is y

∴ The greatest common factor is 6y

- Divide each term by 6y to find the terms in the bracket

∴ 18y³ - 6y = 6y(3y² - 1) ⇒ not the same with the answer

∵ The expression is $32y^{10}-24$

∵ The greatest common factor of 32 and 24 is 8

∴ The greatest common factor is 8

- Divide each term by 8 to find the terms in the bracket

∴ $32y^{10}-24$ = 8( $y^{10}-3$ ) ⇒ the same with the answer

∴ The expression $32y^{10}-24$ = 8( $y^{10}-3$ ) is completely factored

∵ The expression is $20y^{7}+10y^{2}$

∵ The greatest common factor of 20 and 10 is 10

∵ The greatest common factor of $y^{7}$ and y² is y²

∴ The greatest common factor is 10y²

- Divide each term by 10y² to find the terms in the bracket

∴ $20y^{7}+10y^{2}=10y^{2}(2y^{5}+1)$ ⇒ not the same with the answer

∵ The expression is $16y^{5}+12y^{3}$

∵ The greatest common factor of 16 and 12 is 4

∵ The greatest common factor of $y^{5}$ and y³ is y³

∴ The greatest common factor is 4y³

- Divide each term by 4y³ to find the terms in the bracket

∴ $16y^{5}+12y^{3}=4y^{3}(4y^{2}+3)$ ⇒ the same with the answer

∴ The expression $16y^{5}+12y^{3}=4y^{3}(4y^{2}+3)$ is completely factored

The expressions that completely factored are:

$32y^{10}-24$ = 8( $y^{10}-3$ )

$16y^{5}+12y^{3}=4y^{3}(4y^{2}+3)$

3 0

3 years ago