Answer:
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Step-by-step explanation:
Statement is incorrect. Correct form is presented below:
<em>The height </em>
<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>
<em>, where </em>
<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>
We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

(1)
By Quadratic Formula:

,
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
There are two negative roots to the provided polynomial function
f(x) = x⁷ – 2x⁴ + 7x² + 2x – 2
<h3>What is polynomial?</h3>
Polynomial is the combination of variables and constants systematically with "n" number of power in ascending or descending order.

We have a polynomial function:
f(x) = x⁷ – 2x⁴ + 7x² + 2x – 2

Using the zero product property:

After solving:
x = -1, x = -0.853, and x = 0.418 (using the graph method)
Thus, there are two negative roots to the provided polynomial function
f(x) = x⁷ – 2x⁴ + 7x² + 2x – 2
Learn more about Polynomial here:
brainly.com/question/17822016
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By making the surface rougher and to increase the force pushing the surfaces together.
Answer:
n > p + 1 + 7k
Step-by-step explanation:
21k - 3n + 9 > 3p + 12
21k - 3n > 3p + 12 - 9
3n > 3p + 3
3n > 3p + 3 + 21k
n > (3p + 3 + 21k)/3
n > p + 1 + 7k
Answer: Meaghan is right.
Step-by-step explanation:
For a number like:
123.45
the tens place would be the "2" (second number at the left of the decimal point)
The ones place would be the "3" (first number at the left of the decimal point)
Let's suppose that Lily is correct.
Then the quotient of:
43.61/7
Will be a number with two digits in the left of the decimal point.
The smallest number that meets this condition, is the number 10.
Then let's see:
7*10 = 70
then:
70/7 = 10
and:
43.61 < 70
(70 is larger than 43.61)
then:
43.61/7 < 70/7 = 10
Then:
(43.61/7) < 10
This means that our quotient is smaller than 10, then the first digit of the quotient can not be on the tens place.
Then Meaghan is the correct one.
We also could perform the quotient to find:
43.61/7 = 6.23
So yes, Meaghan is correct.