I think it would be 150....
Answer: =65536
Step-by-step explanation: hope this help
There are 4! = 24 poosible permutations of the four letters. Let the letters be A, B, C and D. Two permutations will have only letter A in the correct envelope, two more permutations will have only letter B in the correct envelope, two more will have only letter C in the correct envelope and two more will have only letter D in the correct envelope. Therefore 8 out of the 24 possible permutations will have only one letter with the correct address. The required probability is 8/24 = 1/3.
Answer:
-51
Step-by-step explanation:
<u>Step 1: Solve inside the parenthesis</u>
12 + 3(18 - 42) + 9
<em>12 + 3(-24) + 9</em>
<em />
<u>Step 2: Multiply</u>
12 + 3(-24) + 9
<em>12 - 72 + 9</em>
<em />
<u>Step 3: Combine the first two numbers</u>
(12 - 72) + 9
<em>-60 + 9</em>
<em />
<u>Step 4: Combine the last two numbers</u>
-60 + 9
<em>-51</em>
<em />
Answer: -51
First, you have to change 7 1/3 to an improper fraction which is 22/3.
Then you have to flip the fraction upside down to get the reciprocal.
So the answer is 3/22
