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vodka [1.7K]
3 years ago
11

The constant pressure molar heat capacity of argon, C_{p,m}C

Chemistry
1 answer:
4vir4ik [10]3 years ago
6 0

Answer:

Constant-volume molar heat capacity of argon is 12.47 J K ⁻¹mol⁻¹

Explanation:

Argon is a monoatomic gas that behaves as an ideal gas at 298K.

Using the first law of thermodinamics you can obtain:

Work, Q, for constant pressure molar heat capacity,CP:

CP = (5/2)R

For constant-volume molar heat capacity,CV:

CV = (3/2)R

That means:

2CP/5 = 2CV/3

3/5 = CV / CP

As CP of Argon is 20.79 J K ⁻¹mol⁻¹, CV will be:

3/5 = CV / CP

3/5 = CV / 20.79 J K ⁻¹mol⁻¹

12.47 J K ⁻¹mol⁻¹ = CV

<h3>Constant-volume molar heat capacity of argon is 12.47 J K ⁻¹mol⁻¹</h3>
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Answer:


                 Option-1 (Solubility and Molecular polarity) is the correct answer.


Explanation:


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While the solvent is running the mixture of compounds starts separating from each other. This separation is due to following physical properties.


1) Solubility of Mixture in Solvent:

                                                          In a mixture those compounds which has more solubility in solvent will travel more and will give greater Rf value and the less soluble will left behind with smaller Rf value. Hence due to solubility a mixture of compounds can be separated.


2) Polarity of Molecules:

                                          As the stationary phase (adsorbent material) is polar in nature, so in mixture those compounds which are less polar will less interact with the stationary phase and will travel more with greater Rf value, while, more polar molecules will form stronger interactions with the stationary phase, hence will travel less and therefore, will show smaller Rf values.


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Why are supergiant so bright?
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5.60 g of an unknown gas at STP fills a 500 mL flask. What is the molar mass of the gas
ale4655 [162]

Hey there!

From ideal gas equation we know,  PV = nRT

All the terms have their usual significance.

PV =w/M * RT

( where , n is number of moles = w/M,   we = weight of gas, M = molecular weight of the gas)

Therefore,  PV = wRT/M

At standard conditions ,  value of pressure, P = 1atm and standard temperature, T = 273K

And value of universal gas constant, R = 0.082 lit. atm. K⁻¹.mol⁻¹

Given that, weight of gas,

w = 5.60g and volume of gas,

V = 500mL = 0.5 Liters

Therefore, substituting all the value, we get   :

  Molar mass = 5.60 * 0.082 * 273 / 1 * 0.5

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4 years ago
What is the molarity of the 8.76 g of Na2S dissolved in 0.500 L of solution?
AlexFokin [52]

Answer:

.224 M

Explanation:

To begin, we need to find the molar mass of Na2S

  • Na=22.99g, S=78.05g
  • 2(22.99)+1(32.07)=78.05

To find Molarity, we use the equation M=moles/Liters of solution

We are given grams, so we must divide by the molar mass of Na2S to find moles.

  • 8.76g Na2S / 78.05g/mol Na2S= .112 moles

Now we use our Molarity equation:

  • .112 moles Na2S / .500L of solution = .224 M
6 0
2 years ago
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